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alexandr1967 [171]
4 years ago
10

In a lab, a 30% acid solution is being mixed with a 5% acid solution to create a 10% acid solution. What is the ratio of the amo

unt of the 30% solution to the amount of 5% solution used to create the 10% solution?
1:3
1:4
1:5
1:6
Mathematics
2 answers:
kupik [55]4 years ago
5 0

1:4 is the answer to the question.

masya89 [10]4 years ago
4 0

Answer:

Option B. 1 : 4.

Step-by-step explanation:

In a lab 30% acid solution and 5% acid solution were mixed to prepare 10% acid solution.

We have to calculate the ratio of both the acids should be mixed to prepare 10% acid solution.

Let the volume of 30% solution was used = x ml

and the volume of 5% acid was used = y ml

Therefore the equation will form as

30%.x + 5%.y = 10%.(x + y)

0.30x + 0.05y = 0.10(x + y)

Now we transfer the similar terms in one side of the equation.

0.30x - 0.10x = 0.10y - 0.05y

0.20x = .05y

\frac{x}{y}= \frac{.05}{0.20}

x : y :: 1 : 4

Therefore solutions will be mixed in a ratio of 1 : 4

Option B. 1 : 4 is the right answer.  

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beks73 [17]

Answer:

0.25

Step-by-step explanation:

72% of courses have final exams and 46% of courses require research papers which means probability of 0.72 for courses that have final exams and 0.46 for courses that require research papers.

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6 0
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Answer:

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