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alexandr1967 [171]
3 years ago
10

In a lab, a 30% acid solution is being mixed with a 5% acid solution to create a 10% acid solution. What is the ratio of the amo

unt of the 30% solution to the amount of 5% solution used to create the 10% solution?
1:3
1:4
1:5
1:6
Mathematics
2 answers:
kupik [55]3 years ago
5 0

1:4 is the answer to the question.

masya89 [10]3 years ago
4 0

Answer:

Option B. 1 : 4.

Step-by-step explanation:

In a lab 30% acid solution and 5% acid solution were mixed to prepare 10% acid solution.

We have to calculate the ratio of both the acids should be mixed to prepare 10% acid solution.

Let the volume of 30% solution was used = x ml

and the volume of 5% acid was used = y ml

Therefore the equation will form as

30%.x + 5%.y = 10%.(x + y)

0.30x + 0.05y = 0.10(x + y)

Now we transfer the similar terms in one side of the equation.

0.30x - 0.10x = 0.10y - 0.05y

0.20x = .05y

\frac{x}{y}= \frac{.05}{0.20}

x : y :: 1 : 4

Therefore solutions will be mixed in a ratio of 1 : 4

Option B. 1 : 4 is the right answer.  

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Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

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Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

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As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

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d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

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note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

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