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yanalaym [24]
3 years ago
5

Which event includes an example of a dependent event?

Mathematics
2 answers:
Ganezh [65]3 years ago
4 0
I'm thinking A.... 
Hope this helps. 
aliina [53]3 years ago
4 0

Answer:D

Step-by-step explanation:

usatestprep

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the snowfall total two years ago was 10.2 inches. last years was 20% grater. what’s last years snowfall total
strojnjashka [21]

12.24 inches

you would do 10.2 x 1.2

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3 years ago
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A rectangular flower garden in Samantha's backyard has 260 feet around its edge. The width of the garden is 60 feet.
OlgaM077 [116]

Answer:

100 - 20 = 80 Length Of the Garden

Step-by-step explanation:

So You Can do 20 Ft Minus 100 Because 100 is the Total so Heres a Graph To Show You

Total= 100 Ft

Width= 20

Length=?

Total - Width = Length

100 - 20 = 80 Length Of the Garden

4 0
2 years ago
The speed of water in a whirlpool varies inversely with the radius. If water speed is 2.5 feet per second at a radius of 30 feet
Nata [24]
The speed of the water in the 3 feet radius is 25 feet per second.
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3 years ago
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A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 y
Anestetic [448]

Answer:

\frac{1}{4180}

Step-by-step explanation:

GIVEN: A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 yellow. Three candies are pulled from the bag in succession, without replacement.

TO FIND: What is the probability that the first two candies drawn are orange and the third is green.

SOLUTION:

Total  candies in the bag =57

Probability that first ball is orange, P(A)=\frac{\text{total orange candies in bag}}{\text{total candies in bag}}

                                                       =\frac{3}{57}=\frac{1}{19}

Probability that second ball is orange, P(B)=\frac{\text{total orange candies in bag}}{\text{total candies in bag}}

                                                        =\frac{2}{56}=\frac{1}{28}

Probability that third ball is green, P(C)=\frac{\text{total green candies in bag}}{\text{total candies in bag}}

                                                                 =\frac{7}{55}

Now, probability that first two balls are orange and third is green is

=P(A)\times P(B)\times P(C)

=\frac{1}{19}\times\frac{1}{28}\times\frac{7}{55}

=\frac{1}{19}\times\frac{1}{4}\times\frac{1}{55}

=\frac{1}{4180}

Hence,  probability that first two balls are orange and third is green is \frac{1}{4180}

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3 years ago
PLZ HELP FAST!! LAST MATH QUESTION FOR THE DAY
liberstina [14]

Answer: A C E

Step-by-step explanation:

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