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madam [21]
3 years ago
14

What value of X guarantees that BC || DE?

Mathematics
1 answer:
Gemiola [76]3 years ago
3 0

Answer:

4

Step-by-step explanation:

as BC║DE

so, AD:BD=AE:CE

   or, CE=(BDₓAE)/AD

   or, x=(5×16)/20=4

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Roll two fair dice. Each die has six faces. A. Let A be the event that either a 3 or 4 is rolled first followed by an odd number
zhenek [66]

Answer:

A. 0.16

B. 0.58

C. No

D. Dependent

Step-by-step explanation:

A.

The sampling space has 36 outcomes.

The event A has 6 outcomes (3,1), (3,3), (3,5), (4,1), (4,3),(4,5)

So P(A)= 6/36 = 0.16

B.

The table in the picture shows the 15 outcomes that are not allowed, so there are 36-15 = 21 possible outcomes for B and its probability is 21/36 = 0.58

C.

Are A and B mutually exclusive events?

No since their intersection is not empty, for example (3,1) belongs to both A and B

D.

In order for A and B to be independent, it must happen that

P(A∩B)=P(A)P(B)

A∩B={(3,1),(3,3),(4,1)} so P(A∩B) = 3/36  

whereas

P(A)P(B) = (6/36)(21/36) = (1/6)(7/12)=7/72

So A and B are not independent.

7 0
3 years ago
heights for 16 year old boys are normally distributed with a mean if 68.3 in and a standard deviation of 2.9 in. find the z-scor
allsm [11]
Simple just decide pie by the universe multiplied bye the square rout of a f1 race car most likely leading too yes
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2 years ago
EXPONENTS:<br> What is the value of 7 cubed?<br> A. 14<br> B. 21<br> C. 49<br> D. 343
quester [9]

Answer:

C

Step-by-step explanation:

7*7=49

6 0
3 years ago
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3 years ago
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The average time an individual reads online national news reports is 49 minutes. Assume the standard deviation is 16 minutes and
Olin [163]

Answer:

0.118 is the probability someone will spend no more than 30 minutes reading online national news reports.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 49 minutes

Standard Deviation, σ = 16 minutes

We are given that the distribution of  time an individual reads is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(no more than 30 minutes)

P( x \leq 610) = P( z \leq \displaystyle\frac{30 - 49}{16}) = P(z \leq -1.1875)

Calculation the value from standard normal z table, we have,  

P(x \leq 30) = 0.118 = 11.8\%

0.118 is the probability someone will spend no more than 30 minutes reading online national news reports.

3 0
2 years ago
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