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tiny-mole [99]
3 years ago
6

analyze this situation and determine how much cookie dough is "wasted" when 3-inch cookies are cut. then have each team member c

alculate the amount of dough wasted when a cookie of a different diameter is used. compare results

Mathematics
1 answer:
nydimaria [60]3 years ago
3 0

Answer:

The result is the same.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

Please have a look at the attached photo.  

My answer:

Given the information:

  • square 12 inches wide
  • 3-inch diameter cookies are cut => its radius is: 1.5 inches

Hence we can find some information:

  • The area of the square is: 12^{2}  = 144 square inches
  • The area of a cookies is: r^{2}π = 3.14*1.5^{2} = 7.065 square inches
  • The total number of 3-inch cookies are: 4*4 =16

=> The total area of the cookies is: 16* 7.065 = 113.04 square inches

=> how much cookie dough is "wasted" when 3-inch cookies are cut:

= The area of the square - The total area of the cookies

= 144 - 113.04 = 30.96  square inches

If the diameter is increased to 4 inches => its radius: 2 inches, we have:

  • The area of a cookies is: r^{2}π = 2^{2} *3.14 = 12.56 square inches
  • The total number of 3-inch cookies are: 3*3 =9

=> The total area of the cookies is: 9* 12.56 = 113.04 square inches

=> how much cookie dough is "wasted" when 4-inch cookies are cut:

= The area of the square - The total area of the cookies

= 144 - 113.04 = 30.96  square inches

The result is the same.

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Answer:

30%

Step-by-step explanation:

5+2=7+3=10

3/10=30%

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3 0
2 years ago
What is the equivalent fraction of 4/8​
Svetradugi [14.3K]

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2/4

Step-by-step explanation:

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8 0
3 years ago
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andrew11 [14]
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7 0
2 years ago
Your friend claims that because each midsegment is half as long as the corresponding side of the triangle, the perimeter of the
AlexFokin [52]
Answer:
The claim is correct

Explanation:
Assume the given triangle ABC
perimeter of triangle ABC = AB + BC + CA ............> I

Now, we have:
D is the midpoint of AB, this means that:
AD = DB = (1/2) AB ..........> 1
E is the midpoint of AC, this means that:
AE = EC = (1/2) AC ...........> 2
DE is the midsegment in triangle ABC, this means that:
DE = (1/2) BC ...........> 3
perimeter of triangle ADE = AD + DE + EA
Substitute in this equation with the corresponding lengths in 1,2 and 3:
perimeter of triangle ADE = (1/2) AB + (1/2) BC = (1/2) AC
perimeter of triangle ADE = (1/2)(AB+BC+AC) .........> II

From I and II, we can prove that:
perimeter of triangle ADE = (1/2) perimeter of triangle ABC
Which means that:
perimeter of midsegment triangle is half the perimeter of the original triangle.

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7 0
3 years ago
What should be add to 7 3/5 to get 18
g100num [7]

Answer:

10\frac{2}{5}

Step-by-step explanation:

7\frac{3}{5}  +  x  = 18\\

transformation : 7\frac{3}{5} = \frac{(5*7) + 3}{5}  = \frac{38}{5}

\frac{38}{5}  +  x = 18\\\\x = 18 - \frac{38}{5} = \frac{(5*18) - 38}{5} = \frac{52}{5}

\frac{52}{5} = 10\frac{2}{5}

8 0
3 years ago
Read 2 more answers
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