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KiRa [710]
3 years ago
12

How do you find an area of a triangle when you just have two sides and an angle?

Mathematics
1 answer:
Olenka [21]3 years ago
5 0
You have to use sin, cos, tan and find the length of the last side and other angles. Then you have to put an imaginary line down the middle and use the sin, cos, tan to find the height and then do 1/2 base times height.
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What time is shown on the clock?
Scorpion4ik [409]

Answer:

it is 11:00 o'clock

havea great dayy

3 0
3 years ago
Read 2 more answers
A dozen eggs cost $1.10 in Dover.  In Ensley, the eggs cost 10% more than in Dover.  Find the price of a dozen eggs in Ensley.
Julli [10]
1.10 multiplied by .10 = .11
1.10 + .11 = 1.21

In Ensley, the price of a dozen eggs costs $1.21.

Hope this helps.

5 0
3 years ago
Combine likes terms to create an equivalent expression 1/7 - 3(3/7h -2/7)
Anastasy [175]

\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7}) = \frac{7-9h}{7}

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7})

We have to combine the like terms

From given expression,

\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7})

By distributive property,

The distributive property lets you multiply a sum by multiplying each addend separately and then add the products.

a(b + c) = ab + bc

Therefore,

Solve for brackets using distributive property

\frac{1}{7} - (3 \times \frac{3}{7}h) + (3 \times \frac{2}{7})\\\\\frac{1}{7} - \frac{9h}{7} + \frac{6}{7}

Add 1/7 and 6/7

\frac{1}{7} + \frac{6}{7} -\frac{9h}{7}\\\\\frac{1+6}{7} -\frac{9h}{7}\\\\Simplify\\\\\frac{7}{7}-\frac{9h}{7}\\\\1-\frac{9h}{7}\\\\Simplify\\\\\frac{7-9h}{7}

Thus the equivalent expression is found

5 0
3 years ago
The distance from Earth to the sun is about 9.3 × 10 7th power miles.
AURORKA [14]

<u>Answer:</u>

The distance from earth to sun is 387.5 times greater than distance from earth to moon.

<u>Solution:</u>

Given, the distance from Earth to the sun is about 9.3 \times 10^{7} \mathrm{miles}

The distance from Earth to the Moon is about 2.4 \times 10^{5} \mathrm{miles}

We have to find how many times greater is the distance from Earth to the Sun than Earth to the Moon?

For that, we just have to divide the distance between earth and sun with distance between earth to moon.

Let the factor by which distance is greater be d.

\text { Now, } \mathrm{d}=\frac{\text { distance between sun and earth }}{\text { distance between moon and earth }}=\frac{9.3 \times 10^{7}}{2.4 \times 10^{5}}=\frac{9.3}{2.4} \times 10^{7-5}\\\\=3.875 \times 10^{2}=387.5

Hence, the distance from earth to sun is 387.5 times greater than distance from earth to moon.

5 0
3 years ago
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were​ born
strojnjashka [21]

Answer:

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 335, \pi = \frac{268}{335} = 0.8

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563

For the percentage:

Multiplying the proportions by 100.

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0
3 years ago
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