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k0ka [10]
2 years ago
14

3x-y= 17 -x+y= -7 Help please

Mathematics
1 answer:
AlexFokin [52]2 years ago
8 0

Answer:

y = -2

x = 5

Step-by-step explanation:

3x - y = 17

-x + y = -7

here we can find the sum of the two equations

2x = 10

x = 5

now we can just plug in the value of x to find y

-(5) + y = -7

y = -2

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In which choice do all three points lie on the
spin [16.1K]

Answer:

D (1, 2), (2, 4), (4,8)

Step-by-step explanation:

Points lying on the same line:

If three points lie on the same line, the change in y has to be always the same when x changes by 1.

А. (0, 1), (-1, 3), (1, 3)

(-1,3) to (0,1): x changes by 1, y by -2

(0,1) to (1,3): x changes by 1, y by 2

So these points are not on the same line.

B. (4, 2), (2, 1), (4, -2)

Two values for y when x = 4, so not on the same straight line.

C (0, 0), (8, 0), (0, 8)

Two values for y when x = 0, so not on the same straight line.

D (1, 2), (2, 4), (4,8)

Here, when x changed by 1(from 1 to 2), y changed by 2.

When x changed by 2(from 2 to 4), y changed by 2*2 = 4.

So these points are on a straight line, and D is the correct answer.

4 0
3 years ago
Someone help with this​
Fantom [35]

Step-by-step explanation:

6x2 - x + 3 - (-5x2 + 10x - 1)

6x2 - x + 3 + 5x2 - 10x + 1

Solving like terms

11x2 - 11x + 4

5 0
3 years ago
Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your
BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}

\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}

7 0
3 years ago
PLZ HELP QUICK PLZ
olya-2409 [2.1K]

Answer:

hope this helps you

5 0
3 years ago
Choose the correct algebraic expression: two plus the product of six and a number
mel-nik [20]
2 + 6n because product means multiply so when you combine 6 and n, it ultimately means you’re going to multiply them together
8 0
3 years ago
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