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Sonbull [250]
3 years ago
10

The graph of this quadratic function is a parabola. What is the x-coordinate of the vertex? y = x^2 - 3

Mathematics
1 answer:
Studentka2010 [4]3 years ago
5 0
\bf y = x^2 - 3\implies y=1x^2+0x-3\qquad now
\\\\\\
\textit{vertex of a parabola}\\ \\
\begin{array}{llccll}
y=&1x^2&+0x&-3\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)

so, the x-coordinate is \bf -\cfrac{{{ b}}}{2{{ a}}}
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The given question is a quadratic equation and we can use several methods to get the solutions to this question. The solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

<h3>Quadratic Equation</h3>

Quadratic equation are polynomials with a second degree as it's highest power.

An example of a quadratic equation is

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The equation or formula of quadratic formula is given as

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y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}\\y = \frac{-2 +- \sqrt{2^2 -4 * 24 * (-15)} }{2*24} \\y = \frac{-2+-\sqrt{4+1440} }{48} \\y = \frac{-2+-\sqrt{1444} }{48} \\y = \frac{-2+- 38}{48} \\y = \frac{-2+38}{48} \\y = \frac{3}{4}\\ \\or\\y = \frac{-2-38}{48} \\y = \frac{-40}{48} \\y = -\frac{5}{6}

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