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Sonbull [250]
3 years ago
10

The graph of this quadratic function is a parabola. What is the x-coordinate of the vertex? y = x^2 - 3

Mathematics
1 answer:
Studentka2010 [4]3 years ago
5 0
\bf y = x^2 - 3\implies y=1x^2+0x-3\qquad now
\\\\\\
\textit{vertex of a parabola}\\ \\
\begin{array}{llccll}
y=&1x^2&+0x&-3\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)

so, the x-coordinate is \bf -\cfrac{{{ b}}}{2{{ a}}}
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