This will take me a little bit let me research :)
Answer:
larger atomic radii because they are on the far left, the s-block, of the periodic table. -The ionic radii increase as you go down groups on the periodic table. -Lithium and Beryllium are not examples of this trend because they are both in 2s.
In the vertical direction, take up to be positive and down to be negative. Then the net <u>vertical</u> force would be
5120 N - 4050 N = 1070 N
(it's positive, so the net vertical force is pointing upward)
In the horizontal direction, take right to be positive and left to be negative. Then the net <u>horizontal</u> force would be
950 N - 1520 N = -570 N
(negative means the net horizontal force points to the left)
So the net force on the balloon is the vector
<em>F</em> = (1070 N) <em>i</em> + (-570 N) <em>j</em>
(where <em>i</em> and <em>j</em> are the unit vectors in the horizontal and vertical directions, respectively)
The magnitude of the net force on the balloon is the magnitude of this vector:
<em>F</em> = √((1070 N)² + (-570 N)²)
<em>F</em> ≈ 1212 N
Explanation:
It is given that,
Length of the rod, l = 14 cm = 0.14 m
Charge on the rod, 
We need to find the magnitude and direction of the net electric field produced by the charged rod at a point 36.0 cm to the right of its center along the axis of the rod, z = 36 cm = 0.36 m
Electric field at the axis of the rod is given by :

Where
is the linear charge density of the rod,


E = -7493170.57 N/C
or

Negative sign shows that the electric field is acting in inwards direction. Hence, this is the required solution.