Question

A frog jumps to the left with an average speed of 1.8\,\dfrac{\text m}{\text s}1.8 s m ​ 1, point, 8, start fraction, start text, m, end text, divided by, start text, s, end text, end fractionfor 0.55\,\text s0.55s0, point, 55, start text, s, end text. What was the frog's displacement in meters

Answer 1

Complete Question

A frog jumps to the left with an average speed of 1.8m/s for 0.55s What was the frog's displacement in meters.

Answer:

The  displacement is  $d = -0.99 \ m$

Explanation:

From the question we are told that  

   The average speed is  $v = -1.8 \ m/s$

The  negative sign indicates that the frog jumped to the left (negative x-axis )

   The time taken is  $t = 0.55 \ s$

Generally displacement is mathematically represented as

        $d = v * t$

      $d = -1.8 * 0.55$

      $d = -0.99 \ m$