Answer:
La fuerza eléctrica es -8.2*10⁻⁸ N
Explanation:
El enunciado correcto es: <em>¿Cuál es la fuerza eléctrica sobre el electrón (-1.6 x 10⁻¹⁹c) de un átomo de hidrógeno ejercida por el protón (1.6 x 10⁻¹⁹c)? Supóngase que la distancia entre el electrón y el protón es de 5.3 x 10⁻¹¹ m</em>
Entre dos o más cargas aparece una fuerza denominada fuerza eléctrica. Su valor depende del valor de las cargas y de la distancia que las separa, mientras que su signo depende del signo de cada carga. Las cargas del mismo signo se repelen entre sí, mientras que las de distinto signo se atraen.
La fuerza eléctrica con la que se atraen o repelen dos cargas puntuales en reposo es directamente proporcional al producto de las mismas e inversamente proporcional al cuadrado de la distancia que las separa:
donde:
-
F es la fuerza eléctrica de atracción o repulsión. En el Sistema Internacional (S.I.) se mide en Newtons (N).
- q1 y q2 son lo valores de las dos cargas puntuales. En el S.I. se miden en Culombios (C).
- d es el valor de la distancia que las separa. En el S.I. se mide en metros (m).
- K es una constante de proporcionalidad llamada constante de la ley de Coulomb. Depende del medio en el que se encuentren las cargas. Para el vacío K tiene un valor aproximadamente de 9*10⁹
.
En este caso:
- K= 9*10⁹
Reemplazando:
Resolviendo:
F= -8.2*10⁻⁸ N
<u><em>La fuerza eléctrica es -8.2*10⁻⁸ N</em></u>
Answer:
Most of the frogs have webbed feet which helps them swim. The thin skin between the toes helps them to push through the water. The frog's feet is webbed ,So they can easily swim.. The skin between toes are flexible soo they can freely push and pull it
Explanation:
Answer:
15.4 kg.
Explanation:
From the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
mu+m'u' = V(m+m').................... Equation 1
Where m = mass of the first sphere, m' = mass of the second sphere, u = initial velocity of the first sphere, u' = initial velocity of the second sphere, V = common velocity of both sphere.
Given: m = 7.7 kg, u' = 0 m/s (at rest)
Let: u = x m/s, and V = 1/3x m/s
Substitute into equation 1
7.7(x)+m'(0) = 1/3x(7.7+m')
7.7x = 1/3x(7.7+m')
7.7 = 1/3(7.7+m')
23.1 = 7.7+m'
m' = 23.1-7.7
m' = 15.4 kg.
Hence the mass of the second sphere = 15.4 kg
Explanation:
Initial velocity is 25m/s i.e. u. Final velocity would be zero since the bus stopped. It is noted that the bus deccelartion of 4m/s, so the acceleration should be considered negative of 4m/s I.e. 4m/s. So using third law of motion i.e.
v^2 - u^2= 2as
(0)^2 - (25)^2= -2×4×s {Note here I used minus sign in acceleration}
-625 = -8×s
s=625 ÷ 8
s= 125 m
So bus would cover a distance of 125m before coming to rest.
The kinetic energy of this block-spring when the block has a speed (v) is given by K.E = 1/2 × (M + m/3)v².
<h3>What is kinetic energy?</h3>
Kinetic energy can be defined as a form of energy that is possessed by a person due to its motion or change in speed (acceleration).
<h3>How to calculate kinetic energy?</h3>
Mathematically, kinetic energy can be calculated by using this formula:
K.E = 1/2 × mv²
Where:
- K.E represents the kinetic energy.
- v represents the speed or velocity.
Since the mass of a segment of this spring is dm = (m/l) dx, the kinetic energy for each of its segment would be given by:
dK = 1/2 × (dm)Vx²
This ultimately implies that, the kinetic energy of this block-spring when the block has a speed (v) is given by:
K.E = 1/2 × Mv² + 1/2 × ¹∫₀((x²v²/l²)m/ldx
K.E = 1/2 × (M + m/3)v².
Read more on kinetic energy here: brainly.com/question/15848455
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