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marshall27 [118]
3 years ago
8

I need help please help please please please

Mathematics
1 answer:
alekssr [168]3 years ago
7 0
Problem 1 is asking "the other cost."

It is described in the problem statement as "a cost for every one-tenth of a mile traveled." It is described in the table header as "Mileage Cost in Dollars."

The only value in the "Mileage Cost in Dollars" column is 1, which corresponds to a distance of 1/10 mile. So, it appears the numerical value of "the other cost" is $1 for each tenth-mile traveled.

___
The problem statement does not make clear whether the desired answer is the description of the other cost, or its numerical value.
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3

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Determine if f(x, y) = 10 − x^2 − y^2
Eva8 [605]

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Step-by-step explanation:

f(x,y)=10-x^2-y^2

To find derivative of z w.r.t. x is treat any other variable as a constant.

dz/dx=0-2x-0

dz/dx=-2x

Evaluating this at (7,-3) gives us dz/dx=-2(7)=-14.

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3 years ago
A development economist is studying income growth in a rural area of a developing country. The last census of the population of
kykrilka [37]

Answer:

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can say that the population mean is not singificantly higher than 425.  

Step-by-step explanation:

Data given and notation  

\bar X=433.75 represent the mean height for the sample  

\sigma=\sqrt{2500}=50 represent the population standard deviation for the sample  

n=100 sample size  

\mu_o =425 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean height actually is higher than the mean height for men in 1960, the system of hypothesis would be:  

Null hypothesis:\mu \leq 425  

Alternative hypothesis:\mu > 425  

Since we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{433.75-425}{\frac{50}{\sqrt{100}}}=1.75    

P-value

Since is a one right tail test the p value would be:  

p_v =P(z>1.75)=1-P(z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can say that the population mean is not singificantly higher than 425.  

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