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Taya2010 [7]
3 years ago
5

Out of the 25 students in Mrs. Green's class, 13 have a pet. What percent of the students in Mrs. Green's class has a pet?

Mathematics
1 answer:
Delicious77 [7]3 years ago
5 0

Answer:

<u>52% of Ms. Green's class has a pet.</u>

Step-by-step explanation:

So, I did this as simple as possible. First, I changed 25 to 100 to represent 100%. I multiplied 25 by 4 to get 100, so I then multiplied 13 by 4 to get 52.

25 → 100

13  →  52

So, this means that the answer is 52%.

A way to check, is by looking at the answer and seeing if it looks correct. Most of the time, you will be able to see if your answer is correct just by looking at it.

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The phrase “y less than 7” translates to an equation.<br><br> True or False?
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False, it translates to an inequality.

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Abandoned mines frequently fill with water. Before an abandoned mine can be reopened, the water must be pumped out. The size of
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How many 5 digit license plate can be made using only the digits 2,3,4,5,6,7,8,9 if an odd digit must go first and second and re
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Answer:

1,440

Step-by-step explanation:

if first two digits must be odd, then there are 4x3 or 12 combinations for that

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3 years ago
A random sample is selected from a population with mean μ = 102 and standard deviation σ = 10. For which of the sample sizes wou
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Answer:

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

Step-by-step explanation:

For this case we know that for a random variable X we have the following parameters given:

\mu = 102, \sigma =10

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

8 0
3 years ago
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