All categories

3 years ago

X 5. Solve.

Mathematics

1 answer:

rusak2 [61]3 years ago

3 0

Answer:

2/10*4/10=2/25 aka 0.08 aka rounded is 0.1

Step-by-step explanation:

hope this helps plz give brainliest

You might be interested in

») Which number sentence is true? A 0.35 > 6 7 B, 0.35 <- 6 7

Lady_Fox [76]

Answer:

B because 67 is more than 0.35

3 0

2 years ago

Use the quadratic formula to solve the following equation -3x^2-x-3=0

tigry1 [53]

Answer:

$x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i$ are two roots of equation $-3 x^{2}-x-3=0$

Solution:

Need to solve given equation using quadratic formula.

$-3 x^{2}-x-3=0$

General form of quadratic equation is $a x^{2}+b x+c=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}$

Since $b^{2}-4 a c$ is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

$\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}$

8 0

4 years ago

I need help please.....

fgiga [73]

Answer:

Step-by-step explanation:

Move the decimal to the right 4 times

7 0

3 years ago

Add. (−5x4+6x2−43)+(6x4−x2+12x+12) Express the answer in standard form. Enter your answer in the box.

Elan Coil [88]

Answer:

x^2+12x-15

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Look at the model. What division does it show

Alex

That showed be 20/6 which is 3 with a reminder of 2

7 0

3 years ago