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arsen [322]
3 years ago
8

In a random sample of 60 computers, the mean repair cost was $150. Assume the population standard deviation is $36. Construct a

90% confidence interval for the population mean.
Mathematics
2 answers:
kompoz [17]3 years ago
6 0

Answer:

90% confidence interval for the population mean is 149.01,\ 150.99

Step-by-step explanation:

Given that, in a random sample of 60 computers, the mean repair cost was $150, with the population standard deviation is $36.

Here,

n=60,\mu=150,\sigma=36

In case of 90% confidence interval, Z=1.645

We know that, the confidence interval will be,

=\mu\pm Z\dfrac{\sigma}{n}

Putting all the values,

=150\pm 1.645\times \dfrac{36}{60}

=150\pm 0.987

=149.01,\ 150.99

GaryK [48]3 years ago
3 0
Given that:
x_bar=150, σ=36, n=60
The 90% confidence interval will be found as follows:
+/-1.65(36/sqrt(60))
=+/-1.65(4.64758)
=+/-7.6685
Thus our answer will be:
150+/-7.6685
=157.6685 or 142.3315
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