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Andreyy89
3 years ago
13

At a recent marathon, spectators lined the street near the starting line to cheer for the runners. The crowd lined up 5 feet dee

p on both sides of the street for the first mile. You estimate that 14 people can comfortably fit in a square that measures 5 feet by 5 feet. Using this information, how many people cheered for the runners at the start of the race? 1mile=5280 feet
Mathematics
1 answer:
masha68 [24]3 years ago
5 0

Answer:

29568 people cheered for the runners at the start of the race

Step-by-step explanation:

From the question, the crowd lined up 5 feet deep on both sides of the street for the first mile.

This lined up crowd could be related to a rectangle that is 1 mile long and 5 feet wide.

First, Convert 1 mile to feet

1 mile = 5280 feet

Hence, the length of the rectangle is 5280 feet and the width is 5 feet.

Now, we will determine how many 5 feet by 5 feet square we can get from the 5280 feet by 5 feet rectangle. To do that, we will divide 5280 feet by 5 feet

5280 feet ÷ 5 feet = 1056

Hence, from the rectangle, we can get 1056 5 feet by 5 feet square.

From the question, you estimate that 14 people can comfortably fit in a square that measures 5 feet by 5 feet,

∴ 14 × 1056 people will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.

14 × 1056 = 14784 people

This is the amount of people that will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.

Since the crowd lined up on both sides of the street, then

2 × 14784 people will comfortably fit in the crowed lined up 5 feet deep on both sides of the street for the first mile

2 × 14784 = 29568 people

Hence, 29568 people cheered for the runners at the start of the race.

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Answer:

Force = mass x acceleration

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Step-by-step explanation:

Force = mass x acceleration

Therefore,

acceleration = Force / mass

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3 years ago
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Answer:

The expressions are equivalent

Step-by-step explanation:

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2 years ago
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3 years ago
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8 0
3 years ago
How would I answer this?
Reika [66]

<u>Answer:</u>

C = 145.4°

By creating a system of equations (2 equations) with the information from a problem, we can substitute and solve for the missing variables.

<u>Step-by-step explanation:</u>

Linear pairs are found on a straight line, so they total to 180°.

C + D = 180 ......eq'n [1]

C is seven more than four times D can be represented with this equation:

C = 4D + 7 ........eq'n [2]

We can solve by <u>substituting [2] into [1]</u>, replacing "C".

C + D = 180

4D + 7 + D = 180

Collect like terms

5D + 7 = 180

Subtract 7 from both sides

5D = 173

Divide both sides by 5

D = 173/5

As a decimal, D = 34.6°.

Using eq'n [2], find C. Substitute the value of "D". Solve.

C = 4D + 7

C = 4(173/5) + 7

C = (692/5) + 7

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C = (692+35)/5                Combine into numerator.

C = 727/5

As a decimal, C = 145.4°.

3 0
3 years ago
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