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aleksandrvk [35]
2 years ago
8

How many 4-letter passords can be made using the letters A thought Z if...

Mathematics
1 answer:
Kazeer [188]2 years ago
8 0

Answer:

26^4 if repetition is allowed, 26 \times25\times24\times23 if repetition is not allowed.

Step-by-step explanation:

For the first case, we have a choice of 26 letters <em>each step of the way. </em>For each of the 26 letters we can pick for the first slot, we can pick 26 for the second, and for each of <em>those</em> 26, we can pick between 26 again for our third slot, and well, you get the idea. Each step, we're multiplying the number of possible passwords by 26, so for a four-letter password, that comes out to 26 × 26 × 26 × 26 = 26^4 possible passwords.

If repetition is <em>not </em>allowed, we're slowly going to deplete our supply of letters. We still get 26 to choose from for the first letter, but once we've picked it, we only have 25 for the second. Once we pick the second, we only have 24 for the third, and so on for the fourth. This gives us instead a pretty generous choice of 26 × 25 × 24 × 23 passwords.

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Solve each of the following equations using a method other than the Quadratic Formula.
liraira [26]

Answer:

A)

y^2-6y = 0

or, y(y-6) = 0

or, y = 0 or y = 6

B)

n^2+5n+7 = 7

or, n^2+5n+7-7 = 7-7 ( Subtracting 7 from both sides)

or, n^2+5n = 0

or, n(n+5) = 0

or, n=0 or n= -5

C)

2t^2-14t+3 = 3

or, 2t^2-14t = 0

or, 2t(t-7) = 0

or, t=0 or t=7

D)

1/3x^2+3x-4 = -4

or, 1/3x^2+3x = 0

or, 1/3x(x+9) = 0

or, x=0 or x= -9

E)

Zero is a common solution to each of the equations. This is because each of the equations had a variable outside the parenthesis with an operation of multiplication.

THANK YOU FOR READING.

8 0
2 years ago
I need help!!!! :))))
zlopas [31]

Answer:

A=50.24

Step-by-step explanation:

Your diameter is 8, which makes the radius 4.

The area of a circle is

A = \pi r^{2} \\A = \pi 4^{2}

A=50.24

5 0
2 years ago
Please help me jdjdjd
jeyben [28]
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8 0
3 years ago
How many 5-letter words can be made using exactly 5 of the letters from
kow [346]

The total number of ways by words are formed is 35 ways.

According to the statement

We have given that the 5 letters and we have to make word from them and the letters are repeated as equal to letters in given words.

And we have to find the possible ways.

So, The given words are:

TEXAS and MEXICO

Here X = 2 and E = 2 and all other words are one time used words.

We can find possible ways by use of combination and permutation.

So,

Total number of ways = 3C_{1} ^{5} + 2C_{2} ^{5}

here 3 because three letters are not repeatable and 2 letters are repeated for 2 times.

So,

Total number of ways = 3C_{1} ^{5} + 2C_{2} ^{5}

Total number of ways = 3(\frac{5!}{1!} ) + 2(\frac{5!}{2!*3!} )

Total number of ways = 3(5) + 2(10)

Total number of ways = 15 + 20

Total number of ways = 35.

So, The total number of ways by letters are formed is 35 ways.

Learn more about combination and permutation here

brainly.com/question/11732255

#SPJ1

3 0
1 year ago
A single-engine plane is flying at 30 mph in the direction N 60° E. A wind is blowing from west to east at 15 mph
Ksivusya [100]

Answer:

C on Edge 2020

Step-by-step explanation:

The graph where the 60 degree angle is touching the y axis and air is above ground

7 0
3 years ago
Read 2 more answers
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