(x+7)^2+9=0
Find x with quadratics
2 answers:
Answer:
x = -7 ±3i
Step-by-step explanation:
(x+7)^2+9=0
Subtract 9 from each side
(x+7)^2+9-9=0-9
(x+7)^2=-9
Take the square root of each side
sqrt((x+7)^2) = ±sqrt(-9)
We know sqrt(ab) = sqrt(a) sqrt(b)
x+7 = ±sqrt(-1) sqrt(9)
We know that sqrt(-1) is the imaginary number i
x+7 = ±i *3
x+7 =±3i
Subtract 7 from each side
x+7-7 = -7 ±3i
x = -7 ±3i
Answer:
x = -7 + 3i, -7 - 3i
Step-by-step explanation:
(x + 7)² + 9 = 0
(x + 7)² = -9
(x + 7) = +- 3i
x + 7 = 3i
x = -7 + 3i
x + 7 = -3i
x = -7 - 3i
x = -7 +- 3i
You might be interested in
1q+2x-1 liner #1 liner # is 18% one
Answer:
what. omg what if is this
The answer is -7 :) hope this helps
√29/2 since cotangent deals the reciprocal of tangent and cotangent value is adjacent side/opposite side
Answer:
wait what grade are you in ?
