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zzz [600]
3 years ago
7

An arrow shot into the air is 160t-16t^2 feet above the ground t seconds after its released. During what period of time is the a

rrow above 384 feet?
Please provide breakdown of problem.
Mathematics
1 answer:
solmaris [256]3 years ago
4 0

Answer:

47 seconds

Step-by-step explanation:

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Answer:

Therefore the rate change of height is  \frac{1}{\pi} m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

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The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

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Differentiating with respect to t.

\frac{dV}{dt}=4\pi \frac{dh}{dt}

Putting the value \frac{dV}{dt}

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