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dsp73
3 years ago
11

All of the following are examples of composite numbers except which one?

Mathematics
1 answer:
Nataly [62]3 years ago
5 0
<span>All of the following are examples of composite numbers except which one?

2.</span>
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Solve the Inequality <br>8p&lt;-3​
Sergeeva-Olga [200]

Answer:

p<-3/8

Step-by-step explanation:

8 0
3 years ago
Simplify the expression to a polynomial in standard form. (X+1)(3x^2+9x+2)
OLEGan [10]

Answer:

3x^3 + 12x^2 +11x +2

Step-by-step explanation:

this is also a cube root expanded If that helps

4 0
2 years ago
An angle of 34°. If the arc is 162 feet tall, how far away is the bus? Round to the nearest tenth.
marta [7]

Answer:

the answer is 134 hope this helps.

8 0
3 years ago
There are 10 cards. Each card has one number between 1 and 10, so that every number from 1 to 10 appears once.
pychu [463]

Answer:

When a card is chosen at random with replacement five times, X is the number of times a prime number is chosen.          Here the card is chosen with replacement.  This implies probability for choosing a prime number remains the same as the previously drawn card is replaced.

The sample space= {1,2,3,4,5,6,7,8,9,10}

Prime numbers = {2,3,5,7}

Prob for drawing prime number = 4/10 = 0.4

is the same when replacement is done.

Also there are two outcomes either prime or non prime.  Hence in this case, X the no of times a prime number is chosen, is binomial with p =0.4 and q = 0.6 and n=5


When a card is chosen at random without replacement three times, X is the number of times an even number is chosen.

Prob for an even number = 0.5

But after one card drawn say odd number next card has prob for even number as 5/9 hence each draw is not independent of the other.  Hence not binomial.

When a card is chosen at random with replacement six times, X is the number of times a 3 is chosen.

Here since every time replacement is done, probability of drawing a 3 remains constant = 1/10 = 0.3

i.e. each draw is independent of the other and there are only two outcomes , 3 or non 3. Hence here X is binomial.

When a card is chosen at random with replacement multiple times, X is the number of times a card is chosen until a 5 is chosen

Here X is the number of times a card is chosen with replacement till 5 is chosen.  This is not binomial.  Here probability for drawing nth time correct 5 is  P(non 5 in the first n-1 draws)*P(5 in nth draw) = 0.1^(n-1) (0.9)

Because nCr is not appearing i.e. 5 cannot appear in any order but only in the last draw, this is not binomial.

Step-by-step explanation:


6 0
3 years ago
sam writes on a white board the positive integers from 1 to 6 inclusive once each. she then writes p additional fives and q seve
ASHA 777 [7]

Answer:7

Step-by-step explanation:

This question is on the ukmt junior maths challenge which I'm doing now, out of the options given I got 7, because 2+4+6+5+(5×20)+(7×7)= 166, (then dividing that by the number of numbers to get the mean) so 166÷31= 5.354.....

Also the 3 has a recurring symbol above it

The 7 is times seven so uh yeah<3

5 0
3 years ago
Read 2 more answers
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