Answer:
133.3atm
Explanation:
Given parameters:
Initial volume = 400ft³
Final volume = 3ft³
Initial pressure = 1atm
Unknown:
Final pressure = ?
Solution:
To solve this problem, we apply Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".
Mathematically;
P₁V₁ = P₂V₂
P and V are pressure and volume
1 and 2 are initial and final states;
Insert parameters and solve;
1 x 400 = P₂ x 3
P₂ = 133.3atm
Answer:
B (Final mass of the metal)
Explanation:
The independent variable in this experiment is the amount of acid the scientist pours on the metal, and the only variable in the list dependent on the amount of acid poured on the metal is the final mass of the metal. Therefore, the final mass of the metal is the dependent variable in the experiment.
It will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water.
If it is known that solubility of NaCl is 360 g/L, let's find out how many NaCl is in 30 mL of water:
360 g : 1 L = x g : 30 mL
Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = <span>x g : 30 mL
Now, crossing the products:
x </span>· 1,000 mL = 360 g · 30 mL
x · 1,000 mL = 10,800 g mL
x = 10,800 g ÷ 1,000
x = 10.8 g
So, from 30 mL mixture, 10.8 g of NaCl could be extracted.
Let's calculate the same for 10 mL water instead of 30 mL.
360 g : 1 L = x g : 10 mL
Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = <span>x g : 10 mL
Now, crossing the products:
x </span>· 1,000 mL = 360 g · 10 mL
x · 1,000 mL = 3,600 g mL
x = 3,600 g ÷ 1,000
<span>x = 3.6 g
</span>
<span>So, from 10 mL mixture, 3.6 g of NaCl could be extracted.
</span>
Now, let's compare:
If from 30 mL mixture, 10.8 g of NaCl could be extracted and <span>from 10 mL mixture, 3.6 g of NaCl could be extracted, the ratio is:
</span>3.6/10.8 = 1/3
Therefore, i<span>t will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water.
</span>
Explanation:
1L=1000mL
1dm³=1L
1dm³=1000cm³
29.84ml-29.00ml=0.84ml
Density=mass(g)/volume(cm³)
=6.6g/(0.84cm³)
=?
I believe the answer would be:
A. Three groups of plants—a group fertilized by X, a group fertilized by Y, and a control group with no fertilizer.
I hope this helps.
