Six students are working to simplify the expression shown. Drag each student's answer to a box to show whether it is fully simpl
ified, equivalent to the given expression but not fully simplified, or not equivalent to the given expression.
2 answers:
Answer:
Here, the given expression,
Thus, by the above explanation,
Equivalent and simplified fully = - 16x + 14y -1
Equivalent but not simplified fully = 1) 9 - 16x + 14y-10
2) 2x - 18x + 14y-1
Not equivalent = 1) 2x - 18x + 14 y - 19
2) - 2xy - 1
3) 16x + 14y - 1
The arrows show the appropriate destination for your dragging.
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Combining like terms in the given expression makes it simplify to ...
(2x -18x) +(14y) +(9 -10) = -16x +14y -1
We are to compare this expression with the offered expressions to see if they simplify to the same thing. We'll examine those left-to-right starting with the top row:
- 2x -18x +14y -19 = -16x +14y -19 . . . not the same
- -2xy -1 . . . not the same
- 16x +14y -1 . . . not the same
- 9 -16x +14y -10 = -16x +14y -1 . . . equivalent
- -16x +14y -1 . . . equivalent and simplified
- 2x -18x +14y -1 = -16x +14y -1 . . . equivalent
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Answer:
Option (4)
Step-by-step explanation:
Proportional relationship means,
y ∝ x
y = kx
Here, k = proportionality constant
Therefore, if the graph of a line passes through the origin (0, 0) table will represent the proportional relationship.
From table 1,
For a point (1, 2)
For another point (3, 2)
In both the cases 'k' is not same of constant.
Therefore, table (1) is not proportional.
For table (2),
Line passes through (2, 0).
That means there is a x-intercept → (2, 0)
Therefore, table doesn't represent a proportional relationship.
For table (3),
Line passes through a point (0, 1)
It means given line has a y-intercept → y = 1
Therefore, table doesn't represent a proportional relationship.
For table (4),
Line of this table passes through two points (1, 3) and (2, 6)
Therefore, proportionality constant for the given table is 3.
Now we can graph table (4).
Answer:
Step-by-step explanation:
Hello!
The study variable is:
X: number of customers that recognize a new product out of 120.
There are two possible recordable outcomes for this variable, the customer can either "recognize the new product" or " don't recognize the new product". The number of trials is fixed, assuming that each customer is independent of the others and the probability of success is the same for all customers, p= 0.6, then we can say this variable has a binomial distribution.
The sample proportion obtained is:
p'= 54/120= 0.45
Considering that the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal: p' ≈ N(p;)
The other conditions for this approximation are also met: (n*p)≥5 and (n*q)≥5
The probability of getting the calculated sample proportion, or lower is:
P(X≤0.45)= P(Z≤)= P(Z≤-3.35)= 0.000
This type of problem is for the sample proportion.
I hope this helps!