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Pachacha [2.7K]
1 year ago
10

astronomers estimate that there are about 10 to the power of 11 galaxics in the universe and that each galexy contains about 10

to the power of 11 stars about how many stars are there in the universe
Mathematics
1 answer:
nika2105 [10]1 year ago
3 0

Answer:

10^22

Step-by-step explanation:

= (10^11)(10^11) -> the bases are the same, add the exponents

= 10^22

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Use the sample data and confidence level to construct the confidence interval estimate of the population proportion p. n equals
Alekssandra [29.7K]

Answer:

(0.767,0.833)

Step-by-step explanation:

The 95% confidence interval for population proportion p can be computed as

p-z_{\frac{\alpha }{2} } \sqrt{\frac{pq}{n} }

The z-value associated with 95% confidence level is 1.96.

whereas p=x/n

We are given that x=440 and n=550.

p=440/550=0.8

0.8-1.96\sqrt{\frac{0.8(0.2)}{550} }

0.8-1.96\sqrt{\frac{0.16}{550} }

0.8-1.96\sqrt{0.00029 }

0.8-1.96(0.01706)

0.8-0.03343

0.76657

Thus, the required confidence interval is

0.767<P<0.833  (rounded to 3 decimal places)

Hence, we are 95% confident that our true population proportion will lie in the interval (0.767,0.833)

3 0
3 years ago
What is the constant proportionality of 3 cans and 9 balls
Masja [62]
The constant proportionality is whats left over
3 0
3 years ago
which of the following is the equation of a line in slope intercept form for a line with a slope equal 1/4 and Y intercept at (0
andrezito [222]

Answer: the answer is A

Step-by-step explanation:

4 0
2 years ago
Please helppppppppppppppppppp
Stolb23 [73]

Answer:

50 feet

Step-by-step explanation:

Perimeter is the sum of all of the lengths of the sides.

A triangle has three sides, and three lengths are given, therefore all the sides are given.

The sum of the sides is 20 + 20 + 10 = 50

So the Perimeter is 50 feet

3 0
3 years ago
Read 2 more answers
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ioda

Answer:

Step-by-step explanation:

Mower A: 3.25 / 0.3 = 10.83

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Mower C: 4.25 / 0.24 = 17.71

Mower D: 5.50 / 0.18 = 30.50

Answer: D :)

8 0
3 years ago
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