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elena-s [515]
3 years ago
8

the function g(x) = 8x2 – 48x 65 written in vertex form is g(x) = 8(x – 3)2 – 7. what is the vertex of g(x)? (–3, –7) (3, –7) (2

4, –7) (–24, –7)
Mathematics
2 answers:
Mrac [35]3 years ago
8 0
G(x)=8(x-3)-7
The number in the parentheses has to be changed to positive 3.
You keep the number (-7) the same sign it already is. The vertex is (3,-7)
Alexandra [31]3 years ago
8 0

Answer:

option (2) is correct.

The vertex is (3 , -7)

Step-by-step explanation:

 Given: the function g(x) = 8x^2-48x+65 written in vertex form isg(x) = 8(x-3)^2-7.

We have to write the vertex form of g(x).

For a given quadratic function f(x)=ax^2+bx+c , we can rewrite it in vertex form  f(x)=a(x-h)^2+k , where (h , k) represents the vertex of the function f(x).

For the given quadratic function g(x) = 8x^2-48x+65 written in vertex form is g(x) = 8(x-3)^2-7.

On comparing , we get

h = 3 and k = -7

Thus, the vertex is (3 , -7)

Thus, option (2) is correct.

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y=-1/8

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Add 1/4 to -3/8

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ABC and CBH are right angles

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Find the following rates. Round your answer to the nearest hundredth. a. ? % of 75 = 5 b. ? % of 28 = 140 c. ? % of 100 = 40 d.
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5 0
3 years ago
An independent-measures research study was used to compare two treatment conditions with n= 12 participants in each treatment. T
Maurinko [17]

Answer:

(a) The data indicate a significant difference between the two treatments.

(b) The data do not indicate a significant difference between the two treatments.

(c) The data indicate a significant difference between the two treatments.

Step-by-step explanation:

Null hypothesis: There is no difference between the two treatments.

Alternate hypothesis: There is a significant difference between the two treatments.

Data given:

M1 = 55

M2 = 52

s1^2 = 8

s2^2 = 4

n1 = 12

n2 = 12

Pooled variance = [(n1-1)s1^2 + (n2-1)s2^2] ÷ (n1+n2-2) = [(12-1)8 + (12-1)4] ÷ (12+12-2) = 132 ÷ 22 = 6

Test statistic (t) = (M1 - M2) ÷ sqrt [pooled variance (1/n1 + 1/n2)] = (55 - 52) ÷ sqrt[6(1/6 + 1/6)] = 3 ÷ 1.414 = 2.122

Degree of freedom = n1+n2-2 = 12+12-2 = 22

(a) For a two-tailed test with a 0.05 (5%) significance level and 23 degrees of freedom, the critical values are -2.069 and 2.069.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 falls outside the region bounded by the critical values.

(b) For a two-tailed test with a 0.01 (1%) significance level and 23 degrees of freedom, the critical values are -2.807 and 2.807.

Conclusion:

Fail to reject the null hypothesis because the test statistic 2.122 falls within the region bounded by the critical values.

(c) For a one-tailed test with 0.05 (5%) significance level and 23 degrees of freedom, the critical value is 1.714.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 is greater than the critical value 1.714.

6 0
3 years ago
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