Answer:
δL/δt = 634,38 ft/s
Step-by-step explanation:
A right triangle is shaped by ( y = distance between aircraft and ground which is constant and equal to 405 f ) a person who is at ground level 3040 f away from the tower distance x = 3040 f and the line between the aircraft and the person. Then we can use Pythagoras theorem and write
L ( distance between aircraft and person )
L² = x² + y² or L² = x² + (405)²
Taken partial derivatives with respect to t we get:
2*L*δL/δt = 2*x*δx/t + 0
Then L*δL/δt = x*δx/dt
At the moment of the aircraft passing over the tower
x = 3040 ft δx/δt = 640 ft/s and L = √ ( 3040)² + (405)²
So L = √9241600 + 164025 L = √9405625 L ≈3066,9 ft
Then:
δL/δt = 3040*640/ 3066,9 units [ ft * ft/s / ft ] ft/s
δL/δt = 634,38 ft/s
...........Hope this helps :)
Answer:
See Explanation
Step-by-step explanation:
For an object at temperature T and supposing that the ambient temperature is Ta then we can write the differential equation that typifies the Newton law of cooling as follows;
dT/dt=-k(T-Tₐ)
So
dT/dt = 2 degrees Celsius per minute
T = 70 degrees Celsius
Ta = 25 degrees Celsius
2 = -k(70 - 25)
-k = 2/(70 - 25)
k = - 0.044
Hence we can write;
dT/dt=-(- 0.044)(95-25)
dT/dt= 3 degrees Celsius per minute
Answer:
21.62
Step-by-step explanation:
add them together
Answer:
y=3(x+3)^2-8
Step-by-step explanation:
Vertex form:
y=a(x-h)^2+k
h=-3, k=-8
y=a(x+3)^2-8
sub (-4,-5)
-5=a(-4+3)^2-8
a=3
y=3(x+3)^2-8
