Answer: $21
HOPE THIS HELPS
CAN U PLEASE GIVE ME BRAINLIEST
Answer: I think it is 47.23
Step-by-step explanation: Because 25% of 14.99 = 11.2425 But 35.99+11.2425 dose not seem right so I pretty sure it would be 35.99+11.24= 47.23
-Alissa
Hopefully this is right.... sorry if it is wrong
You need to find common factors. The factors of 88 are 1 and 88, 2 and 44, 4 and 22, and 8 and 11. The factors of thirty are 1 and 30, 2 and 15, and 5 and 6. The greatest common factor is 2 so the ratio is 44:15.
Answer:
4.41 feet per second.
Step-by-step explanation:
Please find the attachment.
We have been given that a man flies a kite at a height of 16 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. We are asked to find how fast must he let out the string when the kite is flying on 34 ft. of string.
We will use Pythagoras theorem to solve for the length of side x as:



Now, we will use Pythagorean theorem to relate x and y because we know that the vertical side (16) is always constant.

Let us find derivative of our equation with respect to time (t) using power rule and chain rule as:

We have been given that
,
and
.





Therefore, the man must let out the string at a rate of 4.41 feet per second.
Can you provide a picture or what is going on in the picture and or text?