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alexandr1967 [171]

3 years ago

8

Use right triangle ABC. The figure is for reference only and is not drawn to scale. In a 30-60-90 triangle, the shorter leg had

a length of 8. What is the length of the longer leg?

1 answer:

miss Akunina [59]3 years ago

5 0

Answer:

In a 30 60 90 triangle, the longer leg = shorter leg * square root (3)

longer leg = 8 * square root (3) = 8 * 1.7320508076

= 13.8564064606

Step-by-step explanation:

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Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long

Ne4ueva [31]

We are given

Jim's backyard:

Length is

$L=15\frac{5}{6} =\frac{95}{6} yards$

width is

$W=10\frac{2}{5} =\frac{52}{5} yards$

Since, this is rectangle

so, we can find area of rectangle

$A=L*W$

$A=(\frac{95}{6})*(\frac{52}{5})$

$A=\frac{494}{3} yard^2$

Area of one sod:

length is

$l=1\frac{1}{3} =\frac{4}{3} yards$

width is

$w=1\frac{1}{3} =\frac{4}{3} yards$

Since, it is rectangle in shape

so,

$Area=l*w$

$A=\frac{4}{3}*\frac{4}{3}$

$A=\frac{16}{9}yard^2$

Number of pieces of sod:

we can use formula

Number of pieces of sod = (area of Jim's backyard)/(area of one sod)

$N=\frac{\frac{494}{3} }{\frac{16}{9} }$

now, we can simplify it

$N=\frac{741}{8}$ pieces need ..............Answer

7 0

3 years ago

Write an equation for the line below.

Dmitry_Shevchenko [17]

Answer:

x = 3

Step-by-step explanation:

A vertical line has the form x = constant. The graph shows the constant you want is 3.

4 0

3 years ago

Identify the equivalent expression for (m^1/3 m^1/5)^0

Lostsunrise [7]

Answer:

1.

Step-by-step explanation:

The thing is, x^0 is always 1. So even if you simplify, it will still be 1.

$(m^\frac{1}{3}*m^\frac{1}{5})^0\\(m^\frac{8}{15})^0\\\text{But when put to the power of 0,}\\1.$

4 0

3 years ago

Read 2 more answers

At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

8 0

3 years ago

How would you round the number 9.9813 x 10-5 to two significant figures? Group of answer choices 10 1.0 x 10-4 10.0 x 10-5 9.9 x

zaharov [31]

Answer:

This Significant Figures Rounding Calculator rounds a given number to the amount of significant digits that you specify. This rounding number which you specify cannot be a negative number and it must be greater than 0. A number with 0 significant digits would be 0.

Step-by-step explanation:

8 0

3 years ago