Answer:
Step-by-step explanation:
The given equation is
We can see that:
This means x=-2 is a zero of p(x).
From the long division in the attachment,
We can rewrite the polynomial as:
We now find solution to the quadratic part:
This is given by:
We plug in the values to get:
Therefore all solutions are:
Answer:
As a rule of thumb, if you know only the two shorter side, their ratio is the tangent of the angle opposed to the side you use as a numerator.
If you know one side and the hypotenuse, the ratio side/hypotenuse is either the sine of the opposite angle, or the cosine of the adjacent angle.
do you need to include the wiggle infront of the first bracket? if not;
(x+1) ÷ [(x^2+2) x (2x-3dx)]
x^2 x 2x = 2x^3
x^2 x -3dx = -3dx^3
2 x 2x = 4x
2 x -3dx = - 6dx
i cant find a way to make it equal 0 so i think the answer is just
x+1 over 2x^3 - 3dx^3 + 4x - 6dx as a fraction
