3 years ago

Solve for x in the equation x^2-8x+41=0?

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

6 0

X = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2

x = ( 8 + sqrt (-100) / 2 and (8 - sqrt(-100) / 2

4 +or- 5i

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