The difference in the given functions is 2x^3 + 6x^2 -8x + 1
<h3>Difference of functions</h3>
Given the following function a shown
f(x)= 2x^3 + 6x^2 -5x - 3
g(x)= 3x-4
Take the difference
(f-g)(x) = f(x) - g(x)
Substitute
(f-g)(x) = 2x^3 + 6x^2 -5x - 3 - (3x - 4)
Expand
(f-g)(x) = 2x^3 + 6x^2 -5x - 3 - 3x + 4
(f-g)(x) = 2x^3 + 6x^2 -8x + 1
Hence the difference in the given functions is 2x^3 + 6x^2 -8x + 1
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Answer:
y -4 = 1/6(x-24)
y = 1/6x -2
Step-by-step explanation:
We can point slope form
y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line
y -4 = 1/6(x-24)
Or we can write slope intercept form
y = mx+b where m is the slope and b is the y intercept
Substituting the points
4 = 1/6(24)+b
4 = 6+b
4-6 = b
-2 =b
y = 1/6x -2
I think eight because if you add those days together they will play again in eight days so that they play on the same day.
Sorry if I got it wrong I tried and that's what counts, right?
2 x - 5 y = 18 / * 4
3 x + 4 y = 4 / * 5 ( we will use the addition method )
--------------------------
8 x - 20 y = 72
+
15 x + 20 y = 20
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23 x = 92
x = 92 : 23
x = 4
8 - 5 y = 18
- 5 y = 18 - 8
- 5 y = 10
y = 10 : ( - 5 )
y = - 2
Answer:
( x, y ) = ( 4, - 2 )
8 since the range is the highest number minus the lowest.
