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tiny-mole [99]
3 years ago
15

I'm under the water on this problem, please help me:

Mathematics
1 answer:
andrew11 [14]3 years ago
5 0

Answer:

See below

Step-by-step explanation:

Okay so...I might be interpreting the question wrong-if I am please comment! I'll fix it to the best of my ability.

A) Plug in -5 to all x values

   f(-5)=10(-5)-3

          ==50-3

    f(-5)= -53

B) f(0)=10(0)-3

    f(0)= -3

C) f(7)=10(7)-3

         =70-3

    f(7)=67

D) f(t^2+2)=10(t^2+2)-3

                 =10t^2+20-3

     f(t^2+2)=10t^2+17

E) f(12-x)=10(12-x)-3

              =120-10x-3

    f(12-x)=117-10x

F) f(x+h)=10(x+h)-3

             =10x+10h-3

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Solution:

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\text{Number of possible sets}\approx 31

Therefore, the number of possible sets at the dance is 31.

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Step-by-step explanation:

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