Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
Answer:
4
Step-by-step explanation:
Answer: x > 5
Step-by-step explanation: To solve for <em>x</em> in this inequality, our goal is the same as it would be if this were an equation, to get x by itself on one side.
Since 3 is being subtracted from x, we add 3 to
both sides of the inequality to get x > 5.
When graphing x > 5, we have an open circle on 5 and the
open circle tells us that 5 is not part of our answer.
Then we draw an arrow going to the right to represent
all possible solutions to this inequality, any number greater than 5.
When you plug 2 in for x, the equation equals 1. The easiest way to go about this is solving the numerator then the denominator. The denominator was equal to 3 and the numerator was equal to 3, thus making 3/3. This equals 1.