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Delvig [45]
2 years ago
14

which table shows the correct values of time and distance for a car traveling at a constant speed of 65 miles per hour?

Mathematics
1 answer:
tino4ka555 [31]2 years ago
4 0

Answer: the one in the top left corner

Step-by-step explanation:

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7x - 22 = 41<br> Im having trouble with this problem
Charra [1.4K]

Answer:

x = 9

Step-by-step explanation:

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6 0
2 years ago
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If f(y) = 2y - 2/5,<br> what is f(f^-1(1024))?
SCORPION-xisa [38]

Answer:

-0.399

Step-by-step explanation:

f^-1(1024)=(2*1024-2/5)^-1= 0.000488

f(0.000488)=2*0.000488-2/5= -0.399

7 0
3 years ago
24 is 0.6% of what number
algol [13]
Hello! The answer would be,
38.4
Since if you do 24x0.6 you would get 14.4 which then you would add
14.4 with 24 and get 38.4
Hope I've helped and feel free to ask me questions!

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8 0
3 years ago
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If x varies directly as y, and x = 7.5 when y = 10, find x when y = 4.
Lilit [14]
The answer is A) 3.
I hope this helps.
7 0
3 years ago
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What is the nth term rule of the quadratic sequence below?
Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

<u>Given sequence</u>:

6, 20, 40, 66, 98, 136, ...

Calculate the <u>first differences</u> between the terms:

6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136

As the first differences are not the same, calculate the <u>second differences:</u>

14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38

As the <u>second differences are the same</u>, the sequence is quadratic and will contain an n² term.

The <u>coefficient</u> of the n² term is <u>half of the second difference</u>.

Therefore, the n² term is:  3n²

Compare 3n² with the given sequence:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

The second operations are different, therefore calculate the differences <em>between</em> the second operations:

3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18

As the differences are the same, we need to add 5n as the second operation:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2  +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2  &-2  & -2  \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

6 0
1 year ago
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