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Ivahew [28]
3 years ago
14

Ok so I need help on this ,asap plz :)

Mathematics
1 answer:
iragen [17]3 years ago
4 0
Number 1 is 4 radical 10

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If tan x = , and 0 &lt; x &lt;<br> , what is cos(x – 3x)?
sweet-ann [11.9K]

Answer:cos  ( − 2 x )

Step-by-step explanation: Subtract  3 x  from  x .

6 0
3 years ago
Can someone hep me with this
Grace [21]

Answer:

What do you need help with?

Step-by-step explanation:

8 0
3 years ago
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For a circle with a radius of 6 feet, what is the measurement of the central angle (in degrees) that intercepts an arc with a le
makkiz [27]

Answer:

135 degrees

Step-by-step explanation:

step 1

Find the circumference of the circle

The circumference is equal to

C=2\pi r

we have

r=6\ ft

substitute

C=2\pi (6)

C=12\pi\ ft

step 2

Remember that the circumference of the circle subtends a central angle of 360 degrees

so

using proportion

Find out the measurement of the central angle (in degrees) that intercepts an arc with a length of 9π/2 ft

\frac{12\pi}{360^o}=\frac{(9\pi/2)}{x}\\\\x=360(9\pi/2)/12\pi\\\\x=135^o

3 0
3 years ago
The cost of breakfast cereal is Rs for 1 kg Calculate how much 25<br>breakfast cereal will cost.​
Irina-Kira [14]

Answer:

25 gram = 1000\35 rs

Step-by-step explanation:

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6 0
3 years ago
Assume that 200 babies are born to 200 couples treated with the XSORT method of gender selection that is claimed to make girls m
JulsSmile [24]

Answer:

a) test statistic = 2.12

b) p-value = 0.017

c) we reject the Null hypothesis

Step-by-step explanation:

Given data :

N = 200

girls (x) = 115 , Boys = 85

p = x / n = 115 / 200 = 0.575

significance level ( ∝ ) = 0.1

<em>aim : test whether the proportion of girls births after the treatment is greater than 50% that occurs without any treatment </em>.

<u>A) Determine the test statistic </u>

H0 : p = 0.5

Ha : p > 0.5

to determine the test statistic we will apply the z distribution at ( ∝ ) = 0.1

Z - test statistic = ( 0.575 - 0.5)  / \sqrt{0.5*0.5 / 200}  = 2.12

<u>b) determine the p-value</u>

The P-value can be determined using the normal standard table

P-value = 1 - p(Z< 2.12 )  =  1 - 0.9830 = 0.017

c) Given that the p value ( 0.017 ) < significance level ( 0.1 )

we will reject the H0 because there is evidence showing that proportion of girls birth is > 50%

3 0
3 years ago
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