Answer: He was 1 minute 28 seconds faster.
Step-by-step explanation:
Hi, to answer this question we simply have to subtract Frankie's time yesterday (29 minutes 49 seconds) to his normal time (31 minutes 17 seconds)
Mathematically speaking:
31m 17s - 29m 49s =
(31m-29 m) (17s-49s)=
2m -32s=
1m 60s -32s=
1m 28s
He was 1 minute 28 seconds faster.
Feel free to ask for more if needed or if you did not understand something.
Feel free to ask for more if needed or if you did not understand something.
Answer:
See below.
Step-by-step explanation:
a.
The first figure has 1 square. The second figure has a column of 2 squares added to the left. The third figure has a column of 3 squares added to the left. Each new figure has a column of squares added to the left containing the same number of squares as the number of the figure.
b.
Figure 10 has 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55 squares.
c.
The formula for adding n positive integers starting at 1 is:
1 + 2 + 3 + ... + n = n(n + 1)/2
For figure 55, n = 55.
n(n + 1)/2 = 55(56)/2 = 1540
d.
Let's use the formula set equal to 190 and solve for n. If n is an integer, then we can.
n(n + 1)/2 = 190
n(n + 1) = 380
We know that 380 = 19 * 20, so n = 19.
Answer: yes
e.
Use the formula above,
S = n(n + 1)/2, where S is the sum.
f.
n(n + 1) = 1478
38 * 39 = 1482
37 * 38 = 1406
|2x + y - 3z|
Plug in the values
|-4 + 10 - 9|
= |-3|
= 3
By definition we have the following equation:
t = d / v
Where,
t: time
d: distance
v: speed
For this case we have:
d / 30 + d / 4 = 17
Rewriting we have:
2d + 15d = 17 (60)
17d = 17 (60)
d = 60 mi
Then, the walking time is
t = d / v
t = 60/4
t = 15 hours
Answer:
She walked
t = 15 hours
Answer:
<u>y ≤ 4</u>
Step-by-step explanation:
Solving :
- Highest y-value is 4
- The other y-values are less than 4
- Hence, the range is : <u>y ≤ 4</u>
