All categories

3 years ago

Https://brainly.com/question/22830500 go to this pleaseee i need help

Mathematics

2 answers:

wel3 years ago

8 0

Answer:

k ill try to help

Step-by-step explanation:

dybincka [34]3 years ago

5 0

1) Parellel because if she had sliced perpendicular, she would have gotten a square and a triangle.

2) Perpendicular because if she had sliced parallel, she would have gotten a (once more) square and a triangle.

1) First shape and Last shape (the cylinder and the cone).

2) First shape and Second shape (the pyramid and the cone).

You might be interested in

A sphere has a diameter of 4 x 10^-3 mm. What is the approximate volume of the sphere? Use 3.14 for pi.

kolezko [41]

Answer:

$3.349 \times {10}^{ - 10} \: {mm}^{3}$

Step-by-step explanation:

$d = 4 \times {10}^{ - 3} \: mm \\ r = 2 \times {10}^{ - 3} \: mm \\ V_{sphere} = \frac{4}{3} \pi {r}^{3} \\ = \frac{4}{3} \times 3.14 \times {(2 \times {10}^{ - 3} )}^{3} \\ = \frac{4}{3} \times 3.14 \times 8\times {10}^{ - 9} \\ = \frac{100.48}{3} \times {10}^{ - 9} \\ = 33.4933333\times {10}^{ - 9} \\ = 33.49 \times {10}^{ - 9} \\ = 3.349 \times {10}^{ - 10} \: {mm}^{3}$

8 0

3 years ago

Before dividing, decompose 420 to make it easier to divide by 4.

den301095 [7]

Answer:

4/420=105

Step-by-step explanation:

decompose 42 and divide by 4 is 10 and is 20 divided by 4 is 5

3 0

3 years ago

Find <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdx%7D%20" id="TexFormula1" title=" \frac{dy}{dx} " alt=" \frac{d

nataly862011 [7]

Answer:

$\displaystyle y' = 2x + 3\sqrt{x} + 1$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients
Anything to the 0th power is 1
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = (x + \sqrt{x})^2$

Step 2: Differentiate

Chain Rule: $\displaystyle y' = 2(x + \sqrt{x})^{2 - 1} \cdot \frac{d}{dx}[x + \sqrt{x}]$
Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y' = 2(x + x^{\frac{1}{2}})^{2 - 1} \cdot \frac{d}{dx}[x + x^{\frac{1}{2}}]$
Simplify: $\displaystyle y' = 2(x + x^{\frac{1}{2}}) \cdot \frac{d}{dx}[x + x^{\frac{1}{2}}]$
Basic Power Rule: $\displaystyle y' = 2(x + x^{\frac{1}{2}}) \cdot (1 \cdot x^{1 - 1} + \frac{1}{2}x^{\frac{1}{2} - 1})$
Simplify: $\displaystyle y' = 2(x + x^{\frac{1}{2}}) \cdot (1 + \frac{1}{2}x^{-\frac{1}{2}})$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = 2(x + x^{\frac{1}{2}}) \cdot (1 + \frac{1}{2x^{\frac{1}{2}}})$
Multiply: $\displaystyle y' = 2[(x + x^{\frac{1}{2}}) + \frac{x + x^{\frac{1}{2}}}{2x^{\frac{1}{2}}}]$
[Brackets] Add: $\displaystyle y' = 2(\frac{2x + 3x^{\frac{1}{2}} + 1}{2})$
Multiply: $\displaystyle y' = 2x + 3x^{\frac{1}{2}} + 1$
Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y' = 2x + 3\sqrt{x} + 1$