Which parabola has the graph shown?

Mathematics

1 answer:

ryzh [129]4 years ago

5 0

The vertex is (-1, 2).

The equation of parabola:

$x=(x-k)^2+h$ where (h, k) is the vertex

We have h = -1 and k = 2.

Substitute:

$x=(y-2)^2-1\ \ \ \ |+1\\\\(x+1)=(y-2)^2$

You might be interested in

Recall that two angles are complementary if the sum of their measures is 90°. find the measures of two complementary angles if

gizmo_the_mogwai [7]

Let one angle be x
Let another angle be 17x
17x+x = 90
18x = 90
x = 90/18 = 5
one angle = x = 5
another angle = 17x =17*5 = 85
I hope it is helpful:D

8 0

3 years ago

Please help, I am on a timer and need help with this question. I will give brainliest

Nady [450]

Answer:

Step-by-step explanation:

Plug in -2 as x into the equation, if it equals y then it is correct ;) hope this helps

8 0

2 years ago

Convert the point slope equation y + 5 = - 3/4(x + 2) into standard form.

inna [77]

Answer: 3x + 4y = - 26

Explanation:

1) the standard form is Ax + By = C

2) given: y + 5 = - (3 / 4) (x + 2)

3) multiply both sides by 4:

4y + 20 = - 3 (x + 2)

4) expand the parenthesis using distributive property:

4y + 20 = -3x - 6

5) transpose -3x and 20

4y + 3x = - 20 - 6

6) combine like terms

4y + 3x = - 26

7) rearrange:

3x + 4y = - 26

That is the standard form of the linear equation given.

8 0

4 years ago

Read 2 more answers

Whoever answers my question will get a brainliest.

Maurinko [17]

Answer:

see explanation

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$