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Fed [463]
3 years ago
11

Find the length of the third side. If necessary, round to the nearest tenth. 4 7

Mathematics
2 answers:
Natalija [7]3 years ago
8 0
Can you show a picture of the question
vitfil [10]3 years ago
4 0

Answer:

The answer would be 8.1

Step-by-step explanation:

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The graph shows how the length of time a bicycle is rented is related to the rental cost. What is the rate of change shown in th
ANTONII [103]

Answer:

A. 2 (I can't really see the graph clearly, I think this is right)

Step-by-step explanation:

(1,4)(2,6)

6-4 =2

2-1 =1

2/1 =2

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3 years ago
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Angle XYZ is bisected by line YW the measure of angle XYW is 52 what is the measurement of angle WYZ what is the measurement of
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Step-by-step explanation:

2(2x+7) = 6x-8

4x + 14 = 6x - 8

2x = 22

x = 11

m<XYZ = 58

m<XYW = 29

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What percent of 80 is 3.2
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Its 4% do i get brainiest???

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Examine the following sequence 1, 4, 9, 16, 25…. Why is 36 the next number in the sequence? Because the pattern is: a. Add the n
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<span>B. Square the number of the term, n</span>
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3 years ago
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Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

7 0
3 years ago
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