Question

PLEASE HELP!!!!Which equation shows y=3/4x−5/2 in standard form?

Answer 1

Answer: 1. A) 3x−4y=10

2. $y=-\frac{x}{4}+3$

3. In the attachment.

Explanation:

1. Given equation=$y=\frac{3}{4}x-\frac{5}{2}$

To reduce it into standard form , multiply both sides by 4,we get

$4y=4(\frac{3}{4}x-\frac{5}{2})\\\Rightarrow4y=3x-10......[distributive\ property]\\\Rightarrow3x-4y=10$ which is option A.

2. Given linear equation : x+4y=12

The standard slope intercept form is given by y=mx+c where m is the slope and c is the constant.

To reduce given linear equation subtract x from both sides, we get

4y=12-x

Divide 4 on both sides.

$\Rightarrow\ y=\frac{12-x}{4}=3-\frac{x}{4}\\\Rightarrow\ y=-\frac{x}{4}+3$ is the slope-intercept form of the linear equation x + 4y = 12.

3. To graph equation $y=\frac{1}{2}x$ on the coordinate plane.

We need to find points to plot the line

Put x=0,we get y=0

Put x=2,we get y=1

Thus we have points (0,0) and (2,1) to plot the line on the graph.

Answer 2

Y = 3/4x - 5/2...subtract 3/4x from both sides
-3/4x + y = -5/2....multiply both sides by -4
3x - 4y = 10 <===
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x + 4y = 12....subtract x from both sides
4y = -x + 12...divide both sides by 4
y = 1/4x + 3 <==
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y = 1/2x.....this will be going thru the origin (0,0)....so start at (0,0)...and since it has a slope of 1/2, go up 1 space and to the right 2 spaces...plot that point...then up 1 and to the right 2...plot that point...keep doing this....and then just connect ur plotted points and u will have ur line