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choli [55]
3 years ago
15

A three-person relay race consists of ten times around a football field. If Tomiko runs three and one-sixth times and Brianna ru

ns two and two-thirds times around the field, how many times around the field does the third person have to run to finish the race?
Mathematics
2 answers:
Brilliant_brown [7]3 years ago
8 0
Four and one-sixth
............
il63 [147K]3 years ago
5 0

Answer: 4 and 1-sixth times

Step-by-step explanation:

Given: The number of times Tomiko runs around football field = 3+\dfrac{1}{6}=\dfrac{19}{6}

The number of times Brianna runs around football field = 2+\dfrac{2}{3}=\dfrac{8}{3}

Total number of times, they had to run = 10

Then, the number of times the third person had to run will be :-

10-\dfrac{19}{6}-\dfrac{8}{3}\\\\=\dfrac{60-19-16}{6}\\\\=\dfrac{25}{6}\\\\=4\dfrac{1}{6}

Hence, the third person has to run 4 and 1-sixth times to finish the race.

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Step-by-step explanation:

the price charged for 100 students reflects the cost per student that applies to the order as a whole.

100 * 6 = $600, so the fixed cost is 750-600 = 150.

...

We can check this by substituting in the other equation.

Does 150*6 + 150 = 1050?

150*6=900

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Yes, it does

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We can express this relationship by the equation:

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