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choli [55]
3 years ago
15

A three-person relay race consists of ten times around a football field. If Tomiko runs three and one-sixth times and Brianna ru

ns two and two-thirds times around the field, how many times around the field does the third person have to run to finish the race?
Mathematics
2 answers:
Brilliant_brown [7]3 years ago
8 0
Four and one-sixth
............
il63 [147K]3 years ago
5 0

Answer: 4 and 1-sixth times

Step-by-step explanation:

Given: The number of times Tomiko runs around football field = 3+\dfrac{1}{6}=\dfrac{19}{6}

The number of times Brianna runs around football field = 2+\dfrac{2}{3}=\dfrac{8}{3}

Total number of times, they had to run = 10

Then, the number of times the third person had to run will be :-

10-\dfrac{19}{6}-\dfrac{8}{3}\\\\=\dfrac{60-19-16}{6}\\\\=\dfrac{25}{6}\\\\=4\dfrac{1}{6}

Hence, the third person has to run 4 and 1-sixth times to finish the race.

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Select each point that is a solution to the system of inequalities described below. NEED IT ASAP​
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Answer:

(1,6),(8,-2)

Step-by-step explanation:

use desmos graphong calculator or imagination

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This graph shows f(x)=4x .<br><br><br> Which graph shows g(x)=4x−4−8 ?
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Answer:

page 3 graph on the left

Step-by-step explanation:

the graph will shift down 8 and to the right 4


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3 years ago
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What's the percentage of four fifths ?
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The answer to your questions is 80%
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Simplify tan9x-tan5x / 1+tan9xtan5x<br> (SHOW WORK)
Charra [1.4K]

Answer:

The simplest form is tan(4x)

Step-by-step explanation:

* Lets revise the identity of the compound angles

- tan(a+b)=\frac{tan(a)+tan(b)}{1-tan(a)tan(b)}

- tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}

* Lets solve the problem

- Let 9x = 5x + 4x

∴ tan(9x) = tan(5x + 4x)

- Use the rule of the compound angle

∵ \frac{tan(9x)-tan(5x)}{1+tan(9x)tan(5x)} ⇒ (1)

∵ tan(5x+4x)=\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)} ⇒ (2)

∵ tan(9x) = equation (2)

- Substitute (2) in (1)

∴ \frac{\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)}-tan(5x)}{1+(\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)})tan(5x)}

- Multiply up and down by (1 - tan(5x)tan(4x))

∴ \frac{tan(5x)+tan(4x)-tan(5x)[1-tan(5x)tan(4x)]}{1-tan(5x)tan(4x)+tan(5x)[tan(5x)+tan(4x)]}

- Simplify up and down

∴ \frac{tan(5x)+tan(4x)-tan(5x)+tan^{2}(5x)tan(4x)}{1-tan(5x)tan(4x)+tan^{2}(5x)+tan(5x)tan(4x) }

∴ \frac{tan(4x)+tan^{2}(5x)tan(4x)}{[1+tan^{2}(5x)]}

- Take tan(4x) as a common factor up

∴ \frac{tan(4x)[1+tan^{2}(5x)]}{[1+tan^{2}(5x)]}

- Cancel [1 + tan²(5x)] up and down

∴ The answer is tan(4x)

4 0
3 years ago
What is the Value of x+y ? PLZ Help ASAP
Natalija [7]
ANSWER

x + y = 60

EXPLANATION

Method 1

Vertically opposite angles are equal, therefore

3x + 55 = 85

This implies that,

3x = 85 - 55

We simplify to get,

3x = 30

Dividing through by 3 gives,

x = 10

Also,

2y - 5 = 95

This implies that,

2x = 95 + 5

We simplify the right hand side to get,

2x = 100

We divide both sides both sides by 2 to get,

x = 50

x + y = 50 + 10

x + y = 60


Method 2

Angles on straight line sums to 180°.



2y-5+85=180


This implies that,

2y+80=180


2y=180-80


2y=100


y=50



Also,


3x+55+95=180


3x+150=180


3x=180-150


3x=30


x=10


x+y=50+10


x+y=60
7 0
3 years ago
Read 2 more answers
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