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anygoal [31]
3 years ago
5

Triangle DEF, with vertices D(2, 5), E(6, 4), and F(3, 3), is reflected across the line y=x. A student determined one of the ver

tices on the image to be (2, –5). Evaluate the student’s answer.
A.
The student performed the reflection correctly.
B.
The student incorrectly reflected across over the x-axis.
C.
The student incorrectly reflected across the y-axis.
D.
The student incorrectly reflected across the line y = –x.
Mathematics
2 answers:
Sonbull [250]3 years ago
6 0

Answer:

B. The student incorrectly reflect the cross over the X axis

Step-by-step explanation:

4vir4ik [10]3 years ago
4 0
The vertices of the image reflected over the line y = x are:
D´( 5 , 2 ),  E´( 4, 6 ) and F´( 3, 3 ).
So ( 2, -5 ) is incorrect and it could be incorrectly reflected across over the x-axis.
Answer: B) 
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3 years ago
The rectangle shown has a perimeter of 156 cm and the given area. Its length is 6 more than five times its width.
Stells [14]
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l=6+5w
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2 years ago
The height, h, in feet of a rock above the ground is given by the equation h = -16t^2 + 24t + 16, where t is the time in seconds
boyakko [2]

The rock will hit the ground at 2 seconds.

Explanation:

Given that the height, h, in feet of a rock above the ground is given by the equation h=-16t^2+24t+16, where t is the time in seconds after the rock is thrown.

We need to determine the time at which the rock will hit the ground.

To determine the time, let us equate the height h = 0 in the equation h=-16t^2+24t+16, we get,

0=-16t^2+24t+16

Switch sides, we have,

-16 t^{2}+24 t+16=0

Let us solve the equation using the quadratic formula.

Thus, we have,

t=\frac{-24 \pm \sqrt{24^{2}-4(-16) 16}}{2(-16)}

Simplifying, we get,

t=\frac{-24 \pm \sqrt{576+1024}}{-32}

t=\frac{-24 \pm \sqrt{1600}}{-32}

t=\frac{-24 \pm 40}{-32}

Hence, the two values of t are

t=\frac{-24 + 40}{-32}   and   t=\frac{-24 -40}{-32}

Simplifying the values, we get,

t=\frac{16}{-32}  and  t=\frac{-64}{-32}

Dividing, we get,

t=-\frac{1}{2}  and  t=2

Since, t cannot negative values, we have,

t=2

Thus, the rock will hit the ground at 2 seconds.

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3 years ago
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