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3 years ago

Reduce anwers to terms simplify improper fractions as mixed 4 1/4 -2 3/4 =

Mathematics

1 answer:

devlian [24]3 years ago

3 0

Answer:

Improper: 3/2

Mixed: 1 1/2

Step-by-step explanation:

I believe this is right, if not feel free to critique me and I will fix it. I'm sorry in advance if it is incorrect.

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Answers to numbers 2 and 3

BARSIC [14]

For both of them you just make them into fraction.
For #2
$\frac{36}{120}$
and then you simplify it
36. ÷12 3
-----. =. --------
120. ÷12 10
After this you want to change the fraction to a percentage.Percentage are out of 100

so you simply will multiply by 10 to the top and bottom
3. 30
----. * 10 =. -----. = 30%
10. 100

The answer is 30%

For number #3
you simply put 63 over 240
63
-----
240
$63 \div 3= 21$
$240 \div 3 = 80$
$\frac{21}{80}$
21
----
80
is that answer because it can't be simplified
after that

4 0

4 years ago

Using point-slope form, write the equation of the line that passes through (2, –1) and has a slope of –5.

erik [133]

Answer: (y+1)=5(x+2)

Step-by-step explanation:

6 0

3 years ago

When a fridge is imported, a customs value of 10% must be paid for its value. If the value of the fridge after paying the custom

Akimi4 [234]

Answer:

55000×100/90

61,111.111

3 0

3 years ago

\large -6x+6y=6<br> \large 6x+3y=12

Kaylis [27]

Answer:

the solution of the system is:

x = 1 and y = 2.

Step-by-step explanation:

I suppose that we want to solve the equation:

-6*x + 6*y = 6

6*x + 3*y = 12

To solve this, we first need to isolate one of the variables in one of the equations.

Let's isolate y in the first equation:

6*y = 6 + 6*x

y = (6 + 6*x)/6

y = 6/6 + (6*x)/6

y = 1 + x

Now we can replace this in the other equation:

6*x + 3*(1 + x) = 12

6*x + 3 + 3*x = 12

9*x + 3 = 12

9*x = 12 - 3 = 9

x = 9/9 = 1

Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.

y = 1 + (1) = 2

Then the solution of the system is:

x = 1 and y = 2.

6 0

3 years ago

help I’ll give brainliest

Tema [17]

Answer: The median of the upper half of a set of data is the upper quartile ( UQ ) or Q3 . The upper and lower quartiles can be used to find another measure of variation call the interquartile range . The interquartile range or IQR is the range of the middle half of a set of data.

Step-by-step explanation:

6 0

3 years ago