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3 years ago

Find the distance between each pair of points. Round your answer to the nearest tenth, if necessary.

Mathematics

1 answer:

devlian [24]3 years ago

3 0

2. (-6,1) (4,0)
√(1)²+(-6-4)²
√1+100
√1+100
The distance is about 10
4. The distance is 6
6. (-2,0) (3,-5)
√(-5-0)²+(3+2)
√25+25
√50
The distance is aproximately 7.1

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Suzanne bakes 350 cookies in 5 hours, and cole bakes 400 cookies in 8 hours Part A: what are the unit rates at which suzanne and

mrs_skeptik [129]

Answer:

Part A: Suzanne bakes 350 in 5 hours and cole bakes 400 in 8 hours. Part B: cole can bake more then suzanne but Suzanne has more time to bake more, so i think suzanne bakes at a faster rate then cole

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3 years ago

What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the la

olga55 [171]

Let's say the first number is "a"
the next consecutive can just be "a+1" and the next, you guessed it, "a+2"
the two smaller ones are a and a+1, the larger one is a+2

now, the product of "a" and "a+1" equals 5 times "a+2" but less by 5

thus a(a + 1) = 5(a + 2) - 5 <----- solve for "a"

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2 years ago

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

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3 years ago

Find the quotient of and express it in the simplest form

nirvana33 [79]

Answer:

No answer can be found

Step-by-step explanation:

There isn't any value to find and express in simplest form lol.

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2 years ago

Mark has been watching 16 movies for the past x months. Max has been trying to keep up with his pace but has only been able to w

egoroff_w [7]

Mark = 16

Max = 8

16 + 8 = 24

144/24 = 6

Option D. 6 months

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3 years ago