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Strike441 [17]
3 years ago
6

What is the range of the relation (-4,1),(-2,0),(8,-1)

Mathematics
1 answer:
mezya [45]3 years ago
3 0

Answer:

Range of the relation is,  {1 , 0, -1}

Step-by-step explanation:

Given: Relation R = {(-4, 1), (-2, 0) , (8, -1)}

To find the range of the relation R;

In the set of ordered pairs, the domain is the set of the  first number in every pair, and the range is the set of the second number of all the pairs.

Then;

Domain of the relation: {-4, -2, 8}

Range of the relation is; {1 , 0, -1}

therefore, the range of the relation is,  {1 , 0, -1}

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I hope this helps you



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How many 2/5 cups of servings are in 10 cups of flour?
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10 / (2/5)...when dividing with fractions, flip what u r dividing by, then multiply
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3 years ago
The percent of working students increased 8.1 to 40.5 what was the present prior to increase
Dmitrij [34]

Answer:

  32.4

Step-by-step explanation:

prior + 8.1 = 40.5 . . . . . . seems to model the problem statement

prior = 32.4 . . . . . . . subtract 8.1 from both sides

Prior to the increase the percent was 32.4.

_____

<em>Comment on the problem statement</em>

When you're talking about a percentage increase in a percentage, it is almost never clear whether you're talking about the percentage of the underlying number, or the percentage of the percentage.

Here, we assume the 8.1 is a percentage of working students, not a percentage of the percentage of workings students. If you actually intend the latter, the percentage before the increase was about 37.465%.

6 0
3 years ago
There are 54 players in a beach volleyball club. Nine of the players cannot attend a game night. The coach needs to make even te
Irina-Kira [14]

Answer:

7/9

Step-by-step explanation:

There are 54 players.

Dividing 54 into 6 gives:54/6=9teams

But 9 players are not at the game,

So 54-9=45

Dividing 45 players into teams of 6 players 45/6=7.5 that is 7 teams and 3 players

Therefore the fraction of players in sixth at the game is=7/9

8 0
3 years ago
The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.65 millimeters and a standard deviat
nexus9112 [7]

Answer:

Two diameters that separate the top 4% and the bottom 4% are 5.77 and 5.53 respectively.

Step-by-step explanation:

We are given that the diameters of bolts produced in a machine shop are normally distributed with a mean of 5.65 millimeters and a standard deviation of 0.07 millimeters.

<em>Let X = diameters of bolts produced in a machine shop</em>

So, X ~ N(\mu=5.65,\sigma^{2} = 0.07^{2})

The z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean

            \sigma = standard deviation

<u>Now, we have to find the two diameters that separate the top 4% and the bottom 4%.</u>

  • Firstly, Probability that the diameter separate the top 4% is given by;

        P(X > x) = 0.04

        P( \frac{X-\mu}{\sigma} > \frac{x-5.65}{0.07} ) = 0.04

        P(Z > \frac{x-5.65}{0.07} ) = 0.04

<em>So, the critical value of x in z table which separate the top 4% is given as 1.7507, which means;</em>

                 \frac{x-5.65}{0.07}  = 1.7507

              x-5.65 = 0.07 \times 1.7507

                         x = 5.65 + 0.122549 = 5.77

  • Secondly, Probability that the diameter separate the bottom 4% is given by;

        P(X < x) = 0.04

        P( \frac{X-\mu}{\sigma} < \frac{x-5.65}{0.07} ) = 0.04

        P(Z < \frac{x-5.65}{0.07} ) = 0.04

<em>So, the critical value of x in z table which separate the bottom 4% is given as -1.7507, which means;</em>

                 \frac{x-5.65}{0.07}  = -1.7507

              x-5.65 = 0.07 \times (-1.7507)

                         x = 5.65 - 0.122549 = 5.53

Therefore, the two diameters that separate the top 4% and the bottom 4% are 5.77 and 5.53 respectively.

4 0
3 years ago
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