Question

I beg someone help.

Answer 1

We will begin by working through Part (a): Simplify √18

To simplify a square root such as the one above, we must factor out perfect square numbers (this means we must find a number that multiplies to 18 and gives a whole number when we square root it). Using our knowledge that √9 is a perfect square, we should factor out a 9 from 18, as modeled below:

√18 = √(9*2)

We can separate this square root into two square roots multiplied together, as shown below:

√(9*2) = √9 * √2

Now, we should simplify √9, which equals 3, because 3 * 3 = 9.

√9 * √2 = 3 * √2 = 3√2

Therefore, √18 = 3√2.

Now, we can move on to the next problem: √6 * √15.

To begin this problem, we can multiply the square roots together, which means multiplying the numbers under the radical.

√6 * √15 = √(6*15) = √90

To simplify this, we use the same process as above:

√90 = √(10 * 9) = √9 * √10 = 3√10

Note: We know that this fully simplified because we cannot factor out another perfect square number from the number under the radical (10).

Therefore, your two answers are 3√2 and 3√10.

Hope this helps!

Answer 2

This was the hardest skill in Algebra for me but I hope it doesn’t have to be for you good luck