Answer:
You can prove this statement as follows:
Step-by-step explanation:
An odd integer is a number of the form 
where 
. Consider the following cases.
Case 1. If 
is even we have: 
.
If we denote by 
we have that 
.
Case 2. if is odd we have: 
.
If we denote by 
we have that
This result says that the remainder when we divide the square of any odd integer by 8 is 1.
2х3+10х+2у2-х-у=2х3+9х+2у2-у=2*3in3+9*3+2*5in2-5=2*27+27+2*25-5=54+27+50-5=126
<span>Length = l</span>
<span>
Width = w</span>
<span>
Perimeter = p = 100
</span>
<span>Perimeter of rectangle = 2(l+w)</span>
<span>
100 = 2 (4w + w)</span>
<span>
100 = 2(5w)</span>
<span>
100 = 10w</span>
<span>
100/10 = w</span>
<span>
10 = w</span>
<span>
w = 10
Area of rectangle = length * width</span>
<span>
a = l*w</span>
<span>
a = 4w*w</span>
<span>
a = 4w^2............(1)</span>
<span>
Put the value of w in (1)</span>
<span>
a = 4(10)^2</span>
<span>
a= 4(100)</span>
<span>
a = 400 yd^2</span>
Answer:
if union, U means plus,+
if intersect means minus, -
Solution= x=5
Alernative form= 21 x - 105= 0<span />
