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3 years ago

How to find the dimension of a triangle

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

6 0

Answer:add the sides

Step-by-step explanation:

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What is the slope of a line that goes through the points 1,-5 and -3,2? I'm helping my niece

a_sh-v [17]

M = (y2 - y1)/(x2-x1)
= 2+5/-3-1
= 7/-4
= -7/4

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3 years ago

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Please help if you know how to integrate using substitution.

mrs_skeptik [129]

Answer:

B. $\displaystyle \frac{-1}{2}ln|cos2x| + C$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Calculus

Antiderivatives - Integrals

Integral Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int {tan(u)} \, du = -ln|cosu| + C$

Step-by-step explanation:

Step 1: Define

$\displaystyle \int {tan(2x)} \, dx$

Step 2: Identify Variables

Set variables for u-substitution.

u = 2x

du = 2dx

Step 3: Integrate

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \frac{1}{2}\int {2tan(2x)} \, dx$
[Integral] U-Substitution: $\displaystyle \frac{1}{2}\int {tanu} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{2}(-ln|cosu|) + C$
[Integral] Back-Substitute: $\displaystyle \frac{-1}{2}ln|cos2x| + C$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration

Book: College Calculus 10e

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2 years ago