Answer: D. This was a random sample. It may have included anyone in attendance.
Step-by-step explanation:
The options are:
A. This was a biased sample. Jim should interview all in attendance.
B. This was a census. Any guest may have participated.
C. This was a random sample. It may not have included anyone in attendance.
D. This was a random sample. It may have included anyone in attendance.
A random sampling is simply referred to as a subset of individuals that are picked from a larger set of individuals.
With regards to the question, Jim wanted to find out what the audience thought about the debate and after the event, he stood at the exit to survey every fifth guest.
This means that it was a random sampling and anyone could have been picked, the sampling wasn't bias.
Answer: It would be a Constant variable.
Hope this helps!
Answer:
~96.6
Step-by-step explanation:
120/124 is 30/31 or 60/62 or 96.6/99.82
Answer:
C.) In perfect health.
Step-by-step explanation:
Given an average weight of 15kg and a standard deviation of 3kg for children of 4 years. Since the weight is based on a normal Z - distribution of 95% which is mean ± 2(standard deviations)
Mean weight interval is :
15 - 2(3) ; 15 + 2(3)
(9 ; 21) ; this weight interval could be interpreted to mean the normal or perfect weight value.
Therefore, given that the child weighs 12kg
Since, 12 kg falls within in the interval, we can conclude that the child is in perfect health.
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