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3 years ago

The graph represents function 1, and the equation represents function 2:

2 answers:

8 0

The rate of change of function 1 (a horizontal line) is zero.

The rate of change (slope) of function 2 is the x-coefficient, 8.

8 is 8 more than 0.

The 4th selection is appropriat:
8

astra-53 [7]3 years ago

4 0

Answer:

Option D.

Step-by-step explanation:

The slope of a horizontal line is 0.

It is given that the function 1 is a horizontal line that passing through the y-axis at y = 4.

It means the rate of change of function 1 is 0.

The slope intercept form of a linear function is

$y=mx+b$ .... (1)

where, m is slope and b is y-intercept.

The function 2 is

$y=8x+12$ .... (2)

On comparing (1) and (2), we get

$m=8$

The rate of change of function 2 is 8.

The difference between rate of change is

$8-0=8$

The rate of change of function 2 is 8 more than the rate of change of function 1.

Therefore, the correct option is D.

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Aplumber charges a $75 flat fee for jobs lasting up to an hour and $30 for each hour of labor after the first hour. Which

tamaranim1 [39]

<h3><u>Answer</u>:- </h3>

$\longrightarrow \sf 75+ 30(h-1)$

<h3><u>Solution:-</u></h3>

<u>Given </u><u>that </u><u>:</u><u>-</u>

job last for h hours
Cost of job lasting more than 1 hour = $30
Cost for the first hour = $75

$\leadsto$ Remaining hours for which the job will last after first hour= (h-1)

<u>Therefore</u>,

Cost for subsequent hours = 30×(h-1)

= 30(h-1)

Total Cost for job = Cost for 1st hour + Cost for subsequent hours

$\quad\quad\quad\quad\quad\quad\quad\quad\boxed{\sf{= 75+30(h-1)}}$

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2 years ago

The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of

ivanzaharov [21]

<h2>Answer:</h2>

$R_2$ is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors $R_1$ and $R_2$ connected together in parallel, the total resistance $R_T$ is given by;

$\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}$ ---------(i)

<em>Make </em> $R_2$ <em> subject of the formula;</em>

=> $\frac{1}{R_2} = \frac{1}{R_T} - \frac{1}{R_1}$

=> $\frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}$

=> ${R_2} = \frac{R_TR_1}{R_1 - R_T}$ ---------------(ii)

From the question,

$R_1$ = 6Ω

$R_T$ = 2Ω

Substitute these values into equation (ii) as follows;

=> ${R_2} = \frac{2*6}{6 - 2}$

${R_2} = \frac{12}{4}$

$R_2$ = 3Ω

Therefore, the value of $R_2$ = 3 ohms or $R_2$ = 3Ω

3 0

3 years ago

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Lana71 [14]

Answer:

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3 years ago

Read 2 more answers

the larger of two number is nine more than four times the smaller number. the sum of the two numbers is fifty-nine. find the two

VLD [36.1K]

This is solved by setting up two equations and then using one to answer the other.
The first step (use what is given to set up the two separate equations)
We are looking for two numbers, let us call them X and Y.
We are told that X + Y = 59
We are also told that (9 more than) 9+ (4times the smaller number) 4Y is the bigger number X
Then we combine that into 9+4Y=X
so we now have two separate equations and we can use one to solve the other. Everywhere we have X in the first equation, we will fill in with the second equation
(9+4Y) +Y = 59 [then combine like terms]
9+5Y=59 [subtract 9 from both sides]
5Y=50 [divide both sides by 5 to isolate the Y]
Y=10 [now plug this into either equation to solve for X]
9+4(10)=X
9+40=X
<u><em>49=X and 10=Y</em></u>

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3 years ago

How much is a gallon of milk in kg

AleksandrR [38]

Answer:

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3 years ago