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muminat
3 years ago
14

Give one word problem involving Pythagorean Theorem and solve the problem completely with steps

Mathematics
1 answer:
Bad White [126]3 years ago
3 0
Sam wants to build a fence splitting her square garden down the middle, diagonally. the width of the original square is 3 yards, and the length is 4 yards. how long should the separating fence be?

answer: 5 yards, as 3^2 + 4^2 = 5^2
You might be interested in
Ramona owns a orange grove, and needs to harvest at least 2616 oranges to cover the costs of running the grove. If each tree bea
GuDViN [60]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following information :

Number of oranges Ramona needs to harvest in other to cover the cost of running the orange Grove = 2616

Average number of oranges each tree bears = 62

Oranges needed for charity donation = 360

Number of orange trees needed in the Grove :

Total number of oranges needed :

(Charity + running the Grove)

(360 + 2616) = 2976 oranges

Number of trees needed = total number of oranges needed / average number of oranges beared per tree

Number of trees needed = 2976 / 62

= 48 trees

Number of trees needed ≥ 48

4 0
3 years ago
Can someone help me please
8_murik_8 [283]

Answer:

2x^2+4x+2

Step-by-step explanation:

(f \circ g)(x)=f(g(x)) \\ \\ =f(x+1) \\ \\ =2(x+1)^2 \\ \\ =2(x^2+2x+1) \\ \\ =2x^2+4x+2

8 0
1 year ago
Read 2 more answers
Which special version of the Pythagorean Theorem can you use to find the length of any squares diagonal, d, using only the lengt
EleoNora [17]

The square's diagonal is the triangle's hypotenuse.

The Pythagorean theorem is = a^{2}+b^{2}=c^{2}

Here, 'c' is the hypotenuse and 'a' and 'b' are the two sides of the triangle.

As the side is given 12 inches, so this becomes

12^{2}+12^{2}=d^{2}

144+144=d^{2}

d^{2}=288

d=\sqrt{288}

d=16.97 inches

6 0
3 years ago
Use the diagram to determine which statement is true
hichkok12 [17]
A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9

B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6

C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16

D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25

The answer is D.
5 0
3 years ago
Read 2 more answers
A train travels train travels 288 kilometre at a uniform speed. If the speed had been 4 kilometre per hour more it would have ta
kiruha [24]

Answer:

Let the speed of the train be x km/h.

Case 1:

Distance = 288 km

Speed = x km/h

Time = Distance/Speed

= 288/x h

Case 2:

Distance = 288 km

Speed = (x+4) km/h

Time = 288/x + 4 h

Since 288/x > 288/x + 4

288/x - 288/x+4 = 1

288[1/x - 1/x+4 ] = 1

[ x + 4 - x / x(x + 4) ] = 1/288

[4 / x^2 + 4x ] = 1/288

x^2 + 4x = 1152

x^2 + 4x - 1152 = 0

x^2 + 36x - 32x - 1152 = 0

x(x + 36) - 32(x + 36) = 0

(x + 36)(x - 32) = 0

x + 36 = 0 , x - 32 = 0

x = -36 , x = 32

x = -36 , rejected since speed cannot be negative.

Therefore , speed of the train = 32 km/h

4 0
3 years ago
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