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lutik1710 [3]
3 years ago
8

A soccer league has 200 players. Of those players 50% are boys. How many boys are in the soccer league

Mathematics
1 answer:
Lelechka [254]3 years ago
7 0
What's 200 minus 50 that's your answer simple
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An amusement park offers an entrance fee discount of 20% to children under 6 years of age and seniors 65 or older. What is the r
Temka [501]

Answer:

  [0, 6) ∪ [65, ∞)

Step-by-step explanation:

Ages under 6 will be in the interval [0, 5], or in the interval [0, 6), as you may wish.

Ages 65 or older will be in the interval [65, ∞).

The union of these two intervals is ...

  [0, 6) ∪ [65, ∞)

5 0
3 years ago
According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e
slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that p = 0.09

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

So

P(X < 4) + P(X \geq 4) = 1

We want P(X \geq 4)

So

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225

P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827

P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082

P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982

Finally

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

6 0
3 years ago
78+24-11+56+23-117+1
kakasveta [241]
78+24+11+56+23+117+1 =310
4 0
3 years ago
The image of parallelogram PQRS after a reflection across Line W Y is parallelogram P'Q'R'S'.
Luden [163]

Answer:

the answer is 6

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Write in simplest radical form.
ipn [44]

Step-by-step explanation:

i think this is the answer if its wrong im sorry

7 0
3 years ago
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