Determine between which consecutive integers the real zeros of each function are located f(x) = 3x3 – 10x2 + 22x – 4

1 answer:

7 0

we have to find which consective integer the real zero is present so for this we will assume
x=0:
f(0)= 3*0-10*0+22*0-4 = -4
now

 for: x=1:
f(1)=3*1-10*1+22*1-4=3-10+22-4=11
now it means that the real zero lies between 0 and 1

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