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viva [34]
3 years ago
5

Prove the identity cos(A+B+C)=cosAcosBcosC-cosAsinBsinC-sinAcosBcosC-sinAsinBcosC

Mathematics
1 answer:
blagie [28]3 years ago
4 0
Hello !

cos (a+b) = cos a cos b - sin a sin b
sin (a+b) = sin a cos b + sin b cos a

cos (a+b+c) = cos (a+(b+c))
cos (a+b+c) = cos a cos (b+c) - sin a sin (b+c)
cos (a+b+c) = cos a (cos b cos c - sin b sin c) - sin a (sin b cos c + sin c cos b)
cos (a+b+c)=cos a cos b cos c - cos a sin b sin c - sin a sin b cos c - sin a cos b sin c
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Step-by-step explanation:

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Step-by-step explanation:

Given [Missing from the question]

L = \frac{3}{8} cm -- Length

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Required

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The volume (V) is calculated as thus:

V = L *W *H

V = \frac{3}{8} cm* \frac{5}{8}cm * \frac{7}{8}cm

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